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3 years ago

What do elements in the same column of the periodic table have in common?

Chemistry

2 answers:

pishuonlain [190]3 years ago

5 0

Answer:

The elements in each group have the same number of electrons in the outer orbital. those outer electrons are also called valence electrons. They are the electrons involved in chemical bonds with other elements.

Oxana [17]3 years ago

5 0

Answer:

They have similar chemical properties!

Explanation:

A column of periodic table is called a group. Elements in a group have similar properties. Like group 1 elements, Lithium and Sodium are extremely reactive. They both fall under same group which is group 1.

They also have same number of valence electrons this is one of the reasons why they have similar chemical properties.

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Of the following states of matter, plasma most closely resembles

Leno4ka [110]

I would have to say it would be the closest to a gas A.

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3 years ago

Find the grams in 1.26*10^-4 mol of HC2H3O2

Oksana_A [137]

Answer:

0.00757 grams

Explanation:

Find the molar mass of the compound: which is 60.05.

The molar mass is basically just the sum of all the atomic masses of each of the elements.

Then multiply the molar mass by the number of moles in the compound, which is 1.26 x 10^-4 moles.

Your answer should be 0.00757 grams.

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3 years ago

The ideal gas heat capacity of nitrogen varies with temperature. It is given by:

hammer [34]

Answer:

A) 1059 J/mol

B) 17,920 J/mol

Explanation:

Given that:

Cp = 29.42 - (2.170*10^-3 ) T + (0.0582*10^-5 ) T2 + (1.305*10^-8 ) T3 – (0.823*10^-11) T4

R (constant) = 8.314

We know that:

$C_p=C_v+R$

We can determine $C_v$ from above if we make $C_v$ the subject of the formula as:

$C_v$ $=C_p-R$

$C_V = 29.42-(2.7*10^{-3})T+(5.82*10^{-7})T2-(1.305*10^{-8})T3-(8.23*10^{-12})T4-8.314$

$C_V = 21.106-(2.7*10^{-3})T+(5.82*10^{-7})T2-(1.305*10^{-8})T3-(8.23*10^{-12})T4$

A).

The formula for calculating change in internal energy is given as:

$dU=C_vdT$

If we integrate above data into the equation; it implies that:

$U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T+(5.82*10^{-7})T2-(1.305*10^{-8})T3-(8.23*10^{-12})T4\,) du$

$U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T/1+(5.82*10^{-7})T2/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)$

$U2-U1= 1059J/mol$

Hence, the internal energy that must be added to nitrogen in order to increase its temperature from 450 to 500 K = 1059 J/mol.

B).

If we repeat part A for an initial temperature of 273 K and final temperature of 1073 K.

then T = 273 K & T2 = 1073 K

∴

$U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})T/1+(5.82*10^{-7})T2/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)$

$U2-U1=\int\limits^{500}_{450}(21.106-(2.7*10^{-3})273/1+(5.82*10^{-7})1073/2-(1.305*10^{-8})T3/3-(8.23*10^{-12})T4/4\,)$

$U2-U1= 17,920 J/mol$

3 0

4 years ago

What does the sun earth and moon have in common

lara [203]

There both in our solar system

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3 years ago

Read 2 more answers

HELP................!!!!

expeople1 [14]

Your answer is 1-3-2-4 , grass sand water rock

3 0

3 years ago