The elements that fill the d orbitals on the periodic table are called transition metals.
Answer:

Explanation:
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In this case, it is possible to determine the pressures of both helium and neon as shown below:

Now, one considers the total moles (addition between both neon's and helium's moles) and the total volume to compute the final pressure as shown below:

Best regards.
Oil doesn't dissolve in water, which could be your answer.
(a) Reaction of nitric acid with non-metal:
C+4HNO
3
⟶CO
2
+2H
2
O+4NO
2
S+6HNO
3
⟶H
2
SO
4
+2H
2
O+6NO
2
(b) Nitric acid showing acidic character:
K
2
O+2HNO
3
⟶2KNO
3
+H
2
O
ZnO+2HNO
3
⟶Zn(NO
3
)
2
+H
2
O
(c) Nitric acid acting as oxidizing agent
P
4
+20HNO
3
⟶4H
3
PO
4
+4H
2
O+20NO
2
3Zn+8HNO
3
⟶3Zn(NO
3
)
2
+4H
2
O+2NO
hope that helps you please mark brainliest