Answer:
Technical program - cosmetologist
<em>M CH₂O₂:</em>
mC + mH×2 + mO₂×2 = 12g + 1g×2 + 16g<span>×2 = <u>46g/mol</u>
:)</span>
The deltaHrxn = -243 kJ/mol the deltaHrxn of CH4(methane) = -802 kJ/mol
The fuel that yields more energy per mole is METHANE. The negative sign merely signifies the release of energy. Thus, 802 kJ/mol is greater than 243 kJ/mol.
The fuel that yields more energy per gram is HYDROGEN. Here is the computation:
deltaHrxn = (-243 kJ/mol)(1 mol/2.016 g H2) <span>= -120.535714286 kJ/g or -121 kJ/g
</span>deltaHrxn of CH4(methane) = (-802 kJ/mol)(1 mol/16.04 g)
<span>= -50 kJ/g
</span>
As discussed the negative sign serves as the symbol of released energy. Thus, 121 is greater than 50.
<u>Answer:</u> The new volume of the gas is 0.11 L
<u>Explanation:</u>
To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.
The equation follows:
where,
are the initial pressure, volume and temperature of the gas
are the final pressure, volume and temperature of the gas
At STP:
The temperature at this condition is taken as 273 K and the pressure at this condition is taken as 1 atm or 101.3 kPa.
We are given:
Putting values in above equation, we get:
Hence, the new volume of the gas is 0.11 L
Answer:
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