Answer:
The right answer is:
Replacing the powdered lead oxide with its large crystals
Removing lead (IV) oxide from the reaction mixture
Using 1.0 gram of lead (IV) oxide
Explanation:
Based on the given information this reaction is the catalytic decomposition of H₂O₂ into water and oxygen using Lead (IV) oxide as a catalyst.
- The catalyst surface area is directly proportional to the reaction rate
- So, Replacing the powdered lead oxide with its large crystals would decrease the reaction rate due to the has larger surface area than its large crystals.
2. Also, Removing lead (IV) oxide from the reaction mixture the reaction rate decreased because as the catalyst is removed.
3. Using 50 cm³ of hydrogen peroxide doesn't affect the rate because the concentration of the reactant doesn't change.
4. Using 1.0 gram of lead (IV) oxide would decrease the reaction rate because the amount of catalyst decreased
So, The right answer is:
Replacing the powdered lead oxide with its large crystals
Removing lead (IV) oxide from the reaction mixture
Using 1.0 gram of lead (IV) oxide
Orbital s is always the first one to fill up
<span>When cooking frozen cheese ravioli, you should use three quarts of water instead of one so that the raviolis have room to move around in the boiling water and so that while they are moving around, they will not stick to each other or the pan.</span>
1.94 * 6. 01 = 11.7 which is approximately same as 11 700. So the answer is 3).
Answer:
No
Explanation:
In the left side of the reaction, there are 6O and 3C but on the right side, there are only 1C and 2O
