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2 years ago

If a crystal lattice structure is so hard, what causes most ionic compounds to be brittle?

Chemistry

2 answers:

KiRa [710]2 years ago

8 0

Explanation:

The cations and anions are locked tightly into place because of the attraction of their opposite charges - as a result, it's difficult to move the ions and the material is very hard.

nasty-shy [4]2 years ago

3 0

Answer:

Explanation:

https://chemistry.stackexchange.com/questions/33322/why-are-so-many-ionic-compounds-brittle

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energy that comes from the heat of the earth's core is known as: solar energy hydro energy geothermal energy wave energy

Alecsey [184]

Energy that comes from the heat of the Earth's core is known as geothermal energy.
Solar energy comes from the Sun, hydro energy from water, and wave energy from wind and waves.

7 0

2 years ago

Read 2 more answers

2H2 +O2 = 2H2O balance equation with 5 oxygen

Ivenika [448]

10H₂ + 5O₂ → 10H₂O

Explanation:

This problem deals with balancing of chemical equations. In balancing chemical equations, the law of conservation of mass must be followed. This states that:

"In a chemical reaction, matter is neither created nor destroyed but transformed from one form to another".

This meaning of this is that; the number of atoms on each side of the expression must be the same.

2H₂ + O₂ → 2H₂O

let us check is the equation above is balanced;

2H₂ + O₂ → 2H₂O

Elements reactant product

H 4 4

O 2 2

We can see vividly that the equation is balanced;

Now; if we have 5 oxygen gas, we multiply the equation through by 5:

5 x ( 2H₂ + O₂ → 2H₂O )

⇒ 10H₂ + 5O₂ → 10H₂O

Elements reactant product

H 20 20

O 10 10

learn more:

Balanced equation brainly.com/question/11102790

#learnwithBrainly

5 0

3 years ago

An ideal gas sealed in a rigid 4.86-L cylinder, initially at pressure Pi=10.90 atm, is cooled until the pressure in the cylinder

seraphim [82]

Answer:

$\Delta H=-11897J$

Explanation:

Hello,

In this case, it is widely known that for isochoric processes, the change in the enthalpy is computed by:

$\Delta H=\Delta U+V\Delta P$

Whereas the change in the internal energy is computed by:

$\Delta U=nCv\Delta T$

So we compute the initial and final temperatures for one mole of the ideal gas:

$T_1= \frac{P_1V}{nR}=\frac{10.90atm*4.86L}{0.082*n}=\frac{646.02K }{n} \\\\T_2= \frac{P_2V}{nR}=\frac{1.24atm*4.86L}{0.082*n}=\frac{73.49K }{n}$

Next, the change in the internal energy, since the volume-constant specific heat could be assumed as ³/₂R:

$\Delta U=1mol*\frac{3}{2} (8.314\frac{J}{mol*K} )*(73.49K-646.02K )=-7140J$

Then, the volume-pressure product in Joules:

$V\Delta P=4.86L*\frac{1m^3}{1000L} *(1.24atm-10.90atm)*\frac{101325Pa}{1atm} \\\\V\Delta P=-4756.96J$

Finally, the change in the enthalpy for the process:

$\Delta H=-7140J-4757J\\\\\Delta H=-11897J$

Best regards.

7 0

3 years ago

The pre-exponential constant and activation energy for the diffusion of iron in cobalt are 1.7 x 10-5 m2/s and 273,300 J/mol, re

Kitty [74]

<u>Answer:</u> The temperature of the system will be 1622 K

<u>Explanation:</u>

The equation relating the pre-exponential factor and activation energy follows:

$\log D=\log D_o-\frac{E_a}{2.303RT}$

where,

D = diffusion coefficient = $2.7\times 10^{-14}m^2/s$

$D_o$ = pre-exponential constant = $1.7\times 10^{-5}m^2/s$

$E_a$ = activation energy of iron in cobalt = 273,300 J/mol

R = Gas constant = 8.314 J/mol.K

T = temperature = ?

Putting values in above equation, we get:

$\log (2.7\times 10^{-14})=\log (1.7\times 10^{-5})-\frac{273,300}{2.303\times 8.314\times T}\\\\T=1622K$

Hence, the temperature of the system will be 1622 K

8 0

2 years ago

1.If we can see something, it MUST be matter. true or false

weeeeeb [17]

Answer:

False

Explanation:

3 0

2 years ago

Read 2 more answers