Explanation:
sun was created through the hypothesis
The lower the angle of the slope, ________ the acceleration along the ramp, therefore, the speed at the bottom of a slope will b
1 answer:
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Answer:
The density of this object is approximately .
The density of the oil in this question is approximately .
(Assumption: the gravitational field strength is )
Explanation:
When the gravitational field strength is , the weight
of an object of mass
would be
.
Conversely, if the weight of an object is in a gravitational field of strength
, the mass
of that object would be
.
Assuming that . The mass of this
-object would be:
.
When an object is immersed in a liquid, the buoyancy force on that object would be equal to the weight of the liquid that was displaced. For instance, since the object in this question was fully immersed in water, the volume of water displaced would be equal to the volume of this object.
When this object was suspended in water, the buoyancy force on this object was . Hence, the weight of water that this object displaced would be
.
The mass of water displaced would be:
.
The volume of that much water (which this object had displaced) would be:
.
Since this object was fully immersed in water, the volume of this object would be equal to the volume of water displaced. Hence, the volume of this object is approximately .
The mass of this object is . Hence, the density of this object would be:
.
(Rounded to )
Similarly, since this object was fully immersed in oil, the volume of oil displaced would be equal to the volume of this object: approximately .
The weight of oil displaced would be equal to the magnitude of the buoyancy force: .
The mass of that much oil would be:
.
Hence, the density of the oil in this question would be:
.
(Rounded to )
Answer:
In the vertical direction the acting forces are the normal force and the weight of the bobsleder plus the sled. In the horizontal direction the acting force is the friciton force.
Explanation:
Hi there!
Please, see the attached figure for a graphic representation of the forces acting on the sled after the bobsleder jumped in.
In the vertical direction, the acting forces are the normal force (N) and the weight of the sled plus the bobsledder (W).
Since the sled is not being accelerated in the vertical direction, the sum of forces in that direction is zero:
∑Fy = W + N = 0 ⇒ W = N
The weight is calculated as follows:
W = (mb + ms) · g
Where:
mb = mass of the bobsleder.
ms = mass of the sled.
g = acceleration due to gravity.
In the horizontal direction the only acting force is the friction force (Fr). The friction force is calculated a follows:
Fr = N · μ
Where:
N = normal force.
μ = kinetic friction coefficient.
Since N = W = (mb + ms) · g
Fr = (mb + ms) · g · μ
If we want to find the acceleration of the sled after the bobsleder jumps in, we can apply Newton's second law:
∑F = m · a
Where "a" is the acceleration and "m" is the mass of the object (in this case, the mass of bobsleder plus the mass of the sled).
∑F = Fr = (mb + ms) · g · μ = (mb + ms) · a
(mb + ms) · g · μ = (mb + ms) · a
Solving for "a":
g · μ = a
