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Bumek [7]
4 years ago
12

The electric force between two charged balloons is 0.16 newtons. If the distance between them is doubled, what will the new forc

e between them be?
A. 0.04 newtons
B. 0.08 newtons
C. 0.32 newtons
D. 0.64 newtons
Physics
2 answers:
stepan [7]4 years ago
7 0

Answer:

Yes, 0.04 newtons is correct. :)

lara31 [8.8K]4 years ago
4 0
<span>So we wan't to know what will the Coulomb force be between two charged baloons will be if we double the distance between the them and Fc=0.16N. The coulomb force between two charges is Fc=k*Q1*Q2/r^2. So we see from the equation that the magnitude of the force will be smaller as we increase the distance. So let's increase the distance from r to R=2r. If we input thai into the equation we get: Fc=k*Q1*Q2/R^2. Now: Fc=k*Q1*Q2/(2r)^2. And finally: Fc= k*Q1*Q2/4r^2. And if we factor out 1/4 we get: Fc=(1/4)*k*Q1*Q2/r^2. Now we can see that if we double the distance the magnitude of the force will be smaller for a factor of 1/4 or the magnitude of the force will be smaller 4 times. So finally the force is (1/4)*0.16N= 0.04N. So the correct answer is A. 0.04 newtons. </span>
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Answer:

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7 0
3 years ago
Read 2 more answers
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Aleonysh [2.5K]

Answer:We can solve this using the Law of Conservation of Momentum. If both marbles are in our system, the initial momentum should equal the final momentum.

The initial momentum can be solved for as so:

*  +  =

(0.06)(0.7) + (0.03)(0) = 0.042 [kg * m/s]

So if the system has an initial momentum of 0.042, it should have the same final momentum.

(0.06)(-0.2) + (0.03)() = 0.042

(0.03)() = 0.54

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Explanation:

5 0
3 years ago
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In uniform circular motion, how does the acceleration change when the speed is increased by a factor of 3? When the radius is de
crimeas [40]

Answer:

The acceleration will become 9/2 times.

a' =9/2 a

Explanation:

We know that acceleration of a particle when it is moving in the circular path is given as

a=\omega^2\ r

r=radius

ω= angular speed

If the speed ω '= 3 ω

If the radius ,r'=\dfrac{r}{2}

The final acceleration =a'

a'=\omega^2'\ r'

a'=(3\omega)^2\times \dfrac{r}{2}

a'=9\omega^2\times \dfrac{r}{2}

a'=\omega^2\times \dfrac{9r}{2}

a'= \dfrac{9r}{2}\times \omega^2\times r

a'=\dfrac{9}{2}a

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5 0
3 years ago
An electric current in a conductor varies with time according to the expression I(t) = 100 sin (120πt) , where I is in amperes a
Mice21 [21]

The  total charge passing a given point in the conductor from t = 0 to t = 1/240 s is 12000π Coulombs

<h3>Total charge through a conductor</h3>

A conductor is a substance that allow current and electricity to pass through it.

The expression that will be used to calculate the current is expressed s:

I(t) = 100 sin (120πt)

where

I is in amperes and t is in seconds.

Since dQ = Idt =  I(t) = 100 sin (120πt)

On integrating

Q = 100*120πcos(120πt) |¹/¹²⁴⁰₀

Substitute the limits

Q = 100 * 120π

Q = 12000π Coulombs

Hence the  total charge passing a given point in the conductor from t = 0 to t = 1/240 s is 12000π Coulombs

Learn more on total charge through a conductor here: brainly.com/question/15083960

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7 0
2 years ago
Suppose you have a device that extracts energy from ocean breakers in direct proportion to their intensity. If the device produc
babymother [125]

Answer:

2.81 kW      

Explanation:

Initial power output, P = 20.0 kW

Initial amplitude, A = 1.20 m

Final Amplitude, A = 0.450 m

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P ∝ E ∝ I ∝ A²

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Substitute the values to find the value of power produced:

P'=\frac{0.450^2}{1.20^2}\times 20.0 kW=2.81 kW

7 0
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