How the Law of Conservation of Matter is supported by the experimental demonstrations?

1 answer:

6 0

The law of conservation of matter states that matter cannot be created nor destroyed. It can only be transformed from one form to another. To state an example where this is shown, let's say a piece of paper is burning. Not having a scientific background, you would say that the matter is being destroyed. But in reality, the paper is simple being transformed to ash, carbon dioxide, and water vapor. Overall, the total mass would still remain the same.

You might be interested in

During a camping trip, Sierra collected dry branches and broke them into smaller pieces. She then placed the sticks in a fire pi

tester [92]

The correct option is this: PHYSICAL CHANGES: BREAKING THE STICKS AND BOILING THE WATER. CHEMICAL CHANGE: LIGHTNING THE FIRE.
In chemistry, a physical change refer to a change in which no new material is formed while a chemical change refers to a change in which a new material is formed. Boiling of water does not change water into another thing, even when the water changes to vapor, it will still turn to water again when it cools down, so boiling is a physical change, so also the breaking of sticks. Lightening a fire on the other hand is a chemical change because a new material is formed and the original material can not be recovered. Putting fire on the sticks will turn the sticks to ashes and the sticks can not be recovered from the ashes, so this is a chemical change.

5 0

3 years ago

At what distance from a long, straight wire carrying a current of 8.7 A is the magnetic field due to the wire equal to the stren

deff fn [24]

Answer:

r= 3.2 cm

Explanation:

Given that

I= 8.7 A

B= 5.4 x 10⁻⁵ T

μo=1.25664 x 10⁻⁶

We know that magnetic filed in wire at a distance r given as

$B=\dfrac{\mu_oI}{2\pi r}$

$r=\dfrac{\mu_oI}{2\pi B}$

By putting the values

$r=\dfrac{1.25664\times 10^{-6}\times 8.7}{2\times \pi \times 5.4\times 10^{-5}}\ m$

r=0.032 m

r= 3.2 cm

5 0

3 years ago

Consider the vector field. f(x, y, z) = xy2z2i x2yz2j x2y2zk (a) find the curl of the vector field?

Marat540 [252]

Observe that the given vector field is a gradient field:

Let $f(x,y,z)=\nabla g(x,y,z)$ , so that

$\dfrac{\partial g}{\partial x} = x y^2 z^2$

$\dfrac{\partial g}{\partial y} = x^2 y z^2$

$\dfrac{\partial g}{\partial z} = x^2 y^2 z$

Integrating the first equation with respect to $x$ , we get

$g(x,y,z) = \dfrac12 x^2 y^2 z^2 + h(y,z)$

Differentiating this with respect to $y$ gives

$\dfrac{\partial g}{\partial y} = x^2 y z^2 + \dfrac{\partial h}{\partial y} = x^2 y z^2 \\\\ \implies \dfrac{\partial h}{\partial y} = 0 \implies h(y,z) = i(z)$