Question

You are designing a pendulum clock to have a period of 1.0 s. The acceleration of gravity is 9.81 m/s2 . How long should the pendulum be? Answer in units of m.

Answer 1

Answer:

0.25 m

Explanation:

The period of a pendulum is given by

$T=2 \pi \sqrt{\frac{L}{g}}$

where  in this case

T = 1.0 s is the period of the pendulum

g = 9.81 m/s^2 is the acceleration due to gravity

L is the length of the pendulum

Re-arranging the equation and solivng for L, we find the length of the pendulum:

$L=g (\frac{T}{2 \pi})^2=(9.81 m/s^2)(\frac{1.0 s}{2\pi})^2=0.25 m$