Kinetic energy=1/2mv^2
=1/2(142*10^-3)(42.9)^2=130.6=131J
Answer:
The positive displacement from the midpoint of its motion at the speed equal one half of its maximum speed is 3.56 cm.
Explanation:
Maximum speed is :
v (max) = Aω
Speed v at any displacement y is given by
=
(
-
) ........................................................ i
And,
v =
v (max)
or, 2 × v = Aω .................................................... ii
Eliminating ω from equations i and ii,
=
(
-
)
or,
= (
)
=(
) 
or, y = 3.56 cm.
Answer:
The magnitude of the force of friction equals the magnitude of my push
Explanation:
Since the crate moves at a constant speed, there is no net acceleration and thus, my push is balanced by the frictional force on the crate. So, the magnitude of the force of friction equals the magnitude of my push.
Let F = push and f = frictional force and f' = net force
F - f = f' since the crate moves at constant speed, acceleration is zero and thus f' = ma = m (0) = 0
So, F - f = 0
Thus, F = f
So, the magnitude of the force of friction equals the magnitude of my push.
Answer:
HERE IS YOUR ANSWER
Explanation:
PLEASE MARK MY ANSWER AS BRAINLIEST IF THE ANSWERS ARE CORRECT .
Beacuse of the loose connection of the wire .
Straight
To solve this problem it is necessary to apply the concepts related to Newton's second law, the definition of density and the geometric relationships that allow us to find the volume of the figures presented.
For the particular case of the Cube with equal sides its volume is determined by


In the case of perforated material we have that its volume is given according to the cylindrical geometry, that is to say



In this way the net volume would be



We need to find the mass, but we have the Weight and Gravity so from Newton's second Law




PART A) From the relation of density as a unit of mass and volume we have to



PART B) To find the weight of the cube then we apply the ratio of



