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3 years ago

All of the following are functions of the skeletal system EXCEPT:

Physics

2 answers:

sasho [114]3 years ago

8 0

I'm pretty sure the answer would be D

VashaNatasha [74]3 years ago

6 0

Answer:

D. Producing ligaments and tendons.

just to the quiz on edge

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If a substance conducts heat easily, it is considered to be agood insulator.bad substance.good conductor.poor conductor.

NARA [144]

If a Substance conducts heat easily then it is considered a good conductor, since the electrons can move freely within the substance.

7 0

3 years ago

Read 2 more answers

A fiber-optic rod consists of a central strand of material surrounded by an outer coating. The interior portion of the rod has a

matrenka [14]

Answer:

The refractive index of the outer coating is 1.52.

Explanation:

Refractive index of interior part, n' = 1.97

critical angle, C = 50.4°

Let the refractive index of the coating is n.

Use the Snell's law,

$n\times sin r = n'\times sinC\\\\n\times sin 90 = 1.97 \times sin 50.4\\\\n = 1.52$

6 0

2 years ago

In a 200-turn automobile alternator, the magnetic flux in each turn is ΦB = 2.50 10-4 cos ωt, where ΦB is in webers, ω is the an

n200080 [17]

Answer:

$10.63952sin(209.43951t)$

10.63952 V

Explanation:

$N_t$ = Number of turns = 200

$\phi_B$ = Magnetic flux = $2.5\times 10^{-4}cos(\omega t)$

$\omega_e$ = Engine angular speed = $1\times 10^{3}\ rpm$

Alternator angular speed is given by

$N_a=2\times \omega_e\\\Rightarrow N_a=2\times 1\times 10^{3}\\\Rightarrow N_a=2\times 10^{3}\ rpm$

$\omega=N_a\dfrac{2\pi}{60}\\\Rightarrow \omega=2\times 10^{3}\dfrac{2\pi}{60}\\\Rightarrow \omega=209.43951\ rad/s$

Induced emf is given by

$\epsilon=-N_t\dfrac{d\phi_B}{dt}\\\Rightarrow \epsilon=-200\dfrac{d}{dt}2.54\times 10^{-4}cos(209.43951 t)\\\Rightarrow \epsilon=200\times 2.54\times 10^{-4}\times 209.43951 sin(209.43951t)\\\Rightarrow \epsilon=10.63952sin(209.43951t)$

The function is $10.63952sin(209.43951t)$

The induced maximum emf is 10.63952 V

5 0

2 years ago

Jupiter's four large moons – Io, Europa, Ganymede, and Castillo – were discovered by Galileo in 1610. Jupiter also has dozens of

Maksim231197 [3]

Answer:

The orbital speed is approximately 17,325.57 m/s

The number of Earth days it would take lo to complete its orbit is approximately 1.77 days

Explanation:

The given parameters are;

The mass of lo, m ≈ 7.22 × 10²² kg

The radius of lo, R ≈ 1.82 × 10⁶ m

The mean distance between Jupiter and lo = 4.22 × 10⁸ m

The orbital equation is given as follows;

$\dfrac{m \cdot v^2}{R} = \dfrac{G \times M \times m}{R^2}$

$\therefore v = \sqrt{\dfrac{G \cdot M}{R} } = \sqrt{\dfrac{ 6.67408 \times 10^{-11} \times 1.898 \times 10^{27}}{4.22 \times 10^8} } = 17,325.57 \ m/s$

The orbital speed ≈ 17,325.57 m/s

The time to complete one orbit = (2 × π × 4.22 × 10⁸)/(17325.57) ≈ 153039.94 s

The time to complete one orbit ≈ 153039.94 s ≈ 1.77 days

The number of Earth days it would take lo to complete its orbit ≈ 1.77 days.

4 0

2 years ago

The energy of a certain charged capacitor is 7 J. What is the new energy stored in that capacitor if its charge is decreased to

poizon [28]

Answer:

The new energy is 1/16 of the original energy

Explanation:

A capacitor is an electric device which is able to store charge when it is connected to a power supply.

The energy stored in a capacitor is given by the equation

$E=\frac{Q}{2C}$

where:

Q is the charge stored on the capacitor

C is the capacitance of the capacitor

For the capacitor in this problem, initially we have

E = 7 J (energy) when the charge stored is Q and the capacitance is C

Later, the charge is decreased to 1/4 of its original value, so the new charge is

$Q'=\frac{1}{4}Q$

Since the capacitance remains the same, the new energy is

$E'=\frac{(\frac{1}{4}Q)^2}{2C}=\frac{1}{16}\frac{Q^2}{2C}=\frac{1}{16}E$

Therefore, the new energy is 1/16 of the original energy.

6 0

3 years ago