Answer:
118750 ml
Explanation:
The chemical equation for complete combustion of hexane is given as;
2C6H14 + 19O2 → 12CO2 + 14H2O
From the equation of the reaction;
2 mol of C6H14 reacts with 19 mol of O2
2 ml of C6H14 reacts with 19 ml of O2
2500 mL of C6H14 would react with x ml of O2
2 = 19
2500 = x
x = 2500 * 19 / 2 = 23750 ml
Since oxygen is 20% of air;
23750 = 20 / 100 * (Volume of air)
Volume of air = 23750 * 100 / 20 = 118750 ml
Answer:
Following laboratory safety guidelines minimizes the chance of lab accidents.
Explanation:
The kind of reaction involving the transfer of electrons or hydrogen away from a molecule is called oxidation.
In the same vein, the molecule that receives the electron or the hydrogen atom is said to be reduced. This means that oxidation cannot exist in isolation without reduction.
In other words, oxidation is defined as:
- Loss of electrons
- Loss of hydrogen atoms
- Gain of oxygen atoms
- Gain in oxidation number
While reduction is defined as:
- Gain of electrons
- Gain of hydrogen atom
- Loss of oxygen atom
- Reduction in oxidation number
More on oxidation/reduction reactions can be found here: brainly.com/question/3867774
Answer:
385.69 g of O₂
Solution:
The Balance Chemical equation for said reaction is as follow;
2 H₂ + O₂ → 2 H₂O
According to Equation,
4.032 g ( 2 mol) H₂ reacts to produce = 36.03 g (2 mol) of H₂O
So,
48.6 g H₂ on reaction will produce = X g of H₂O
Solving for X,
X = (48.6 g × 36.03 g) ÷ 4.032 g
X = 434.29 g of H₂O
It means that the H₂ provided is in Excess. Therefore, the yield of product (H₂O) is being controlled by O₂ (Limiting Reagent).
So, According to Equation,
36.03 g (2 mol) H₂O is produced by = 31.998 g (1 mol) of O₂
So,
434.29 g of H₂O will be produced by = X g of O₂
Solving for X,
X = (434.29 g × 31.998 g) ÷ 36.03 g
X = 385.69 g of O₂
times concentration OH-