Answer:
It takes 20 minutes and 24 seconds more on Friday than that of normal days.
Explanation:
Given:
Average speed on normal days (s₁) = 115 km/h = 71 mi/h
Time taken on normal days (t₁) = 1 hr and 13 min
Average speed on Friday (s₂) = 90 km/h = 56 mi/h
Time taken on Friday (t₂) = ?
Distance covered is same in both case.
Converting time from minutes to hours using the conversion factor, we have:
1 min =
hour
∴ 13 min = ![\frac{13}{60}=0.22\ h](https://tex.z-dn.net/?f=%5Cfrac%7B13%7D%7B60%7D%3D0.22%5C%20h)
So, ![t_1=1\ h+0.22\ h=1.22\ h](https://tex.z-dn.net/?f=t_1%3D1%5C%20h%2B0.22%5C%20h%3D1.22%5C%20h)
Using the distance formula for both the days, we get:
![d=speed\times time\\\\d=s_1t_1\\d=s_2t_2](https://tex.z-dn.net/?f=d%3Dspeed%5Ctimes%20time%5C%5C%5C%5Cd%3Ds_1t_1%5C%5Cd%3Ds_2t_2)
Therefore,
![s_1t_1=s_2t_2\\\\115\ km/h\times 1.22\ h=90\ km/h\times t_2\\\\t_2=\frac{140.3\ km}{90\ km/h}\\\\t_2=1.56\ hrs](https://tex.z-dn.net/?f=s_1t_1%3Ds_2t_2%5C%5C%5C%5C115%5C%20km%2Fh%5Ctimes%201.22%5C%20h%3D90%5C%20km%2Fh%5Ctimes%20t_2%5C%5C%5C%5Ct_2%3D%5Cfrac%7B140.3%5C%20km%7D%7B90%5C%20km%2Fh%7D%5C%5C%5C%5Ct_2%3D1.56%5C%20hrs)
So, time taken on Friday is 1.56 hours.
Time taken on Friday is more and the difference is given as:
Time difference = Time taken on Friday - Time on normal days
Time difference = 1.56 - 1.22 = 0.34 hours
Converting time from hours to minutes using the conversion factor, we have:
1 hour = 60 min
∴ 0.34 hours = 0.34 × 60
= 20.4
= 20 mins + 0.4 mins
= 20 min + (0.4 × 60) = 20 mins + 24 s
So, it takes 20 min and 24 seconds more on Friday than that of normal days.