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aleksandr82 [10.1K]
2 years ago
8

If a skydiver jumps out of a plane horizontally (in other words with no initial vertical velocity), then what will her vertical

speed be after having fallen a vertical distance of 50.8m if you neglect air resistance over that distance?
Physics
1 answer:
erastovalidia [21]2 years ago
4 0

The final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

<h3>Time of motion of the girl</h3>

The time of motion of the girl is calculated as follows;

h = vt + ¹/₂gt²

where;

  • v is initial vertical velocity = 0
  • t is time of motion
  • g is acceleration due to gravity

Substitute the given parameters and solve for time of motion;

50.8 = 0 + ¹/₂(9.8)t²

2(50.8) = 9.8t²

101.6 = 9.8t²

t² = 101.6/9.8

t² = 10.367

t = √10.367

t = 3.22 seconds

<h3>Final vertical velocity of the skydiver</h3>

vf = vi + gt

where;

vi is the initial vertical velocity = 0

vf = 0 + 9.8(3.22)

vf = 31.56 m/s

Thus, the final vertical velocity of the skydiver at 50.8 m of fall is 31.56 m/s.

Learn more about vertical velocity here: brainly.com/question/24949996

#SPJ1

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