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labwork [276]
3 years ago
11

The position of a particle is given by the expression x = 2.00 cos (6.00πt + 2π/5), where x is in meters and t is in seconds det

ermine the position of the particle at t = 0.330 s
Physics
1 answer:
Nana76 [90]3 years ago
8 0
The position of the particle at time t is
x(t) = 2.00 \cos (6.00 \pi t+ \frac{2}{5}\pi )
If we substitute t=0.330 s, we find
x(0.330 s)=2.00 \cos (6.00 \pi (0.330 s) +  \frac{2}{5}  \pi)=
=2.00 \cos (1.98 \pi +  0.40 \pi )=2.00 \cos (2.38 \pi) =
=2.00 \cdot (-0.72)=-1.45 m
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Thermodynamic Processes
goblinko [34]

Answer:

A. Part a is the attachment

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Explanation:

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We write equation as

workdone =(PaVa)ln\frac{Vb}{Va}

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W1 = 25 x 0.693

= 17.327kj

The isochoric expansion has no change in volume. So,

W2 = 0

Isothermal compression

w3=nRT3ln\frac{Vd}{Vc}

T3 = constant temperature

nRT3 = PcVc = PdVd

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Pc = 1mpa Vc = 10L Vd = 5L

w3=(1)(10)ln\frac{5L}{10L}

= 10x-0.693

= -6.93kj

Isochoric compression has no change in volume. Workdone w4 = 0

Total workdone = w1 + w2 + w3 + w4

= 17.33 + 0 + (-6.93) + 0

= 10.4kj

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2 years ago
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Black_prince [1.1K]

Answer:

The answer to your question is given below

Explanation:

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Divide both side by wavelength

Frequency = Velocity /wavelength

Keeping the velocity constant, we have:

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From the above illustration, we can see clearly that the frequency and wavelength are in inverse relationship. This implies that the higher the frequency, the shorter the wavelength and the shorter the frequency, the higher the wavelength.

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Answer:

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