Answer:
Therefore the amplitude of the resultant wave is
Explanation:
The equation of wave:
y=A sin (kx-ωt)
For wave 1:
y₁=A sin (kx-ωt) = sin (kx-ωt)
For wave 2:
y₂=A sin (kx-ωt+Φ) = sin (kx-ωt+Φ)
Where A= amplitude=
The angular frequency
,
= wave length.
t= time
T= Time period
= phase difference =
The resultant wave will be
y = y₁ + y₂
= sin (kx-ωt) +
sin (kx-ωt+Φ)
{sin (kx-ωt) + sin (kx-ωt+Φ)}
Therefore the amplitude of the resultant wave is
Answer:
1752.14 tonnes per year.
Explanation:
To solve this exercise it is necessary to apply the concepts related to power consumption and power production.
By conservation of energy we know that:
Where,
Production of Power
Consumption of power
Where the production of power would be,
Where,
m = Total mass required
Energy per Kilogram
Efficiency
The problem gives us the aforementioned values under a production efficiency of 45%, that is,
Replacing the values we have,
Solving for m,
We have the mass in kilograms and the time in seconds, we need to transform this to tons per year, then,
tonnes per year.
Answer:
b. 40V , 40V
Explanation:
Connections are as per the figure.
As total current through source is 4A , current through each lamp is 1A.
As total resistance of the circuit is 10Ω ,resistance of each bulb is 40Ω because in case of a parallel circuit in which identical objects are connected , where R is the resistance of each bulb and n is the number of bulbs.
As per Ohm's law , voltage of the source =IR = 4×10 =40V.
We can see from the figure that if the voltage across the source is 40V , the voltage across each bulb is also 40V.
