1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anna35 [415]
3 years ago
15

What is the stopping distance if the car is initially traveling at speed 6.0v? assume that the acceleration due to the braking i

s the same in both cases?
Physics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0
The distance for any rectilinear motion at constant acceleration is:

d = v₀t + 0.5at²
where
v₀ is the initial velocity

So, if v₀ = 6v, and it stopped to 0 m/s, then the acceleration is equal to:
a = (0 - 6v)/t = -6v/t
Thus,
d = (6v)(t) + (0.5)(-6v/t)(t²)
d = 6vt - 3t
<span>d = 3t(2v - 1)</span>
You might be interested in
If a car travels 216 kilometers in 4 hours, calculate its speed.
Mariana [72]

Answer:

15 m/s

Explanation:

Speed(m/s) = distance(m)/time(s)

distance = 216 km = 216,000 m

time = 4 hours = 14,400 s

speed = 216000/14400 = 15 m/s

6 0
2 years ago
Read 2 more answers
I am unique even though there are billions of me no two are the same what am I
Aleksandr [31]
I think the answer is Snow flakes
6 0
3 years ago
Read 2 more answers
As the Sun ages, what will happen to life here on Earth? Why?
Burka [1]

Answer:

As the Sun ages it will enter another stage of stellar evolution where it's atmosphere begins to inflate.As the Sun heats up and expands, life on Earth will become increasingly difficult. Long before the Sun becomes a red giant some 4 or 5 billion years from now, our planet will be rendered uninhabitable.

~I HOPE IT HELPS♡

5 0
3 years ago
Two objects gravitationally attract with a force of 100 N. If the mass of one object is doubled and the mass of the other object
barxatty [35]

Hello!

Recall the equation for gravitational force:
F_g = \frac{Gm_1m_2}{r^2}

Fg = Force of gravity (N)
G = Gravitational constant

m1, m2 = masses of objects (kg)
r = distance between the objects' center of masses (m)

There is a DIRECT relationship between mass and gravitational force.

We are given:
F_g = 100N

If we were to double one mass and triple another, according to the equation:
F'_g = \frac{G(2m_1)(3m_2)}{r^2} = 6(\frac{G(m_1)(m_2)}{r^2}) = 6F_g

Thus:
6 * F_g = 6 * 100 = \boxed{600N}

5 0
3 years ago
A student performs this experiment and measures the bar to have a mass of 150g and length of 36cm. What is the moment of inertia
Ugo [173]

Answer:

The moment of inertia of the bar is 45\times10^{-4}\ kg-m^2

Explanation:

Given that,

mass of bar = 150 g

Length l = 36 cm

We need to calculate the moment of inertia of the bar

Using formula of moment inertia

I=\dfrac{1}{12}Ml^2

Where,

M = mass of the bar

L = length of the bar

Put the value into the formula

I=\dfrac{1}{12}\times150\times10^-3\times36\times10^{-2}

I=45\times10^{-4}\ kg-m^2

Hence, The moment of inertia of the bar is 45\times10^{-4}\ kg-m^2

4 0
4 years ago
Other questions:
  • If a sprinter has an average acceleration of 9.5 m/s2, how long does it take for the person to go from rest to 10 m/s
    15·1 answer
  • A girl coasts down a hill on a sled, reaching
    12·1 answer
  • Water flows steadily through a fire hose and nozzle. The hose is 78 mm inside diameter, and the nozzle tip is 20 mm I.D.; water
    9·1 answer
  • The basic barometer can be used to measure the height of a building. If the barometric readings at the top and the bottom of a b
    5·1 answer
  • Tìm chỉ số của A1 và A2
    11·1 answer
  • Through what potential difference must an electron be accelerated from rest to have a de Broglie wavelength of 500 nmnm
    10·1 answer
  • What is your zodiac sign?
    7·1 answer
  • Hey guys who is on.......
    9·2 answers
  • In order for work to happen you MUST have?
    5·1 answer
  • a single rectangular slit of width of 50 is illuminated by red light with a wavelength of 600 nm. a screen is placed a certain d
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!