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Anna35 [415]
3 years ago
15

What is the stopping distance if the car is initially traveling at speed 6.0v? assume that the acceleration due to the braking i

s the same in both cases?
Physics
1 answer:
Sunny_sXe [5.5K]3 years ago
4 0
The distance for any rectilinear motion at constant acceleration is:

d = v₀t + 0.5at²
where
v₀ is the initial velocity

So, if v₀ = 6v, and it stopped to 0 m/s, then the acceleration is equal to:
a = (0 - 6v)/t = -6v/t
Thus,
d = (6v)(t) + (0.5)(-6v/t)(t²)
d = 6vt - 3t
<span>d = 3t(2v - 1)</span>
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How many Joules of energy are required to run a 100W light bulb for one day?
Vlada [557]

The following are the answers to the questions presented:

a. The joules of energy required to run a 100W light bulb for one day is 8640000J
b. The amount of coals that has to be burned to light that light bulb for one day is 0.96kg

The solution would be like this for this specific problem:

<span>P=<span>W/s</span>→W=Pt=100W1day <span><span>24h/</span><span>1day </span></span><span><span>3600s/</span><span>1h</span></span>=8640000J</span>

<span>W=<span>30/100</span>wm→m=<span><span>100W/</span><span>30w</span></span>=<span><span>100×8640000J/</span><span>30×30×<span>10in thepowerof6 </span><span>J/<span>kg</span></span></span></span>=0.96kg</span>

<span>I am hoping that these answers have satisfied your queries and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.</span>

4 0
3 years ago
Select the correct definition for each of the following terms:
777dan777 [17]

Answer:

1)A

2)B

3)C

4) D

5) C

Explanation:

1)

System is an isolation of matter that has been chosen out of the universe and studied.

2)

Surroundings are everything outside the system that interacts with the matter within the system externally

3)

Thermal energy is associated with constant random motion of atoms and molecules associated with Temperature.

4)

Chemical energy is the energy stored in the bonds between the atoms and molecules. Breaking and making of these bonds lead to releasing and absorbing of energy to surroundings.

5)

Kinetic Energy is the energy associated with the motion of the particles.

6 0
3 years ago
A circular coil that has 100 turns and a radius of 10.0 cm lies in a magnetic field that has a magnitude of 0.0650 T directed pe
yulyashka [42]

Answer:

(a) 0.204 Weber

(b) 0.22 Volt

Explanation:

N = 100, radius, r = 10 cm = 0.1 m, B = 0.0650 T, angle is 90 degree with the plane of coil, so theta = 0 degree with the normal of coil.

(a) Magnetic flux, Ф = N x B x A

Ф = 100 x 0.0650 x 3.14 x 0.1 0.1

Ф = 0.204 Weber

(b) B1 = 0.0650 T, B2 = 0.1 T, dt = 0.5 s

dB / dt = (B2 - B1) / dt = (0.1 - 0.0650) / 0.5 = 0.07 T / s

induced emf, e = N dФ/dt

e = N x A x dB/dt

e = 100 x 3.14 x 0.1 x 0.1 x 0.07 = 0.22 V

6 0
3 years ago
A bell is rung. What best describes the density of air around the bell? The air density does not change. The air density increas
dezoksy [38]

I think the closest possible answer to this question is The air density increases and decreases repeatedly before returning to normal.Thank you for your question. Please don't hesitate to ask in Brainly your queries. 
7 0
3 years ago
Read 2 more answers
By what potential difference must a proton [m_0 = 1.67E-27 kg) be accelerated to have a wavelength lambda = 4.23E-12 m? By what
Vinil7 [7]

Explanation:

1. Mass of the proton, m_p=1.67\times 10^{-27}\ kg

Wavelength, \lambda_p=4.23\times 10^{-12}\ m

We need to find the potential difference. The relationship between potential difference and wavelength is given by :

\lambda=\dfrac{h}{\sqrt{2m_pq_pV}}

V=\dfrac{h^2}{2q_pm_p\lambda^2}

V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 1.67\times 10^{-27}\times (4.23\times 10^{-12})^2}

V = 45.83 volts

2. Mass of the electron, m_p=9.1\times 10^{-31}\ kg

Wavelength, \lambda_p=4.23\times 10^{-12}\ m

We need to find the potential difference. The relationship between potential difference and wavelength is given by :

\lambda=\dfrac{h}{\sqrt{2m_eq_eV}}

V=\dfrac{h^2}{2q_em_e\lambda^2}

V=\dfrac{(6.62\times 10^{-34})^2}{2\times 1.6\times 10^{-19}\times 9.1\times 10^{-31}\times (4.23\times 10^{-12})^2}

V=6.92\times 10^{34}\ V

V = 84109.27 volt

Hence, this is the required solution.

7 0
3 years ago
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