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Nataly [62]
3 years ago
12

What is the direction of the centripetal force when applied to an object?

Physics
2 answers:
iren [92.7K]3 years ago
4 0

The answer is C. Perpendicular to an object's motion

mihalych1998 [28]3 years ago
3 0
For an object moving in a path that's a circle or a part of one,
the centripetal force acts in the direction toward the center of
the circle.  That direction is perpendicular to the way the object
is moving.
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.A force is used to lift a 75-kg mass to a height in 2 sec. It does 9800 J of worl
Nataly_w [17]

Answer:

It is raised to the height of 13.1 meters.

Explanation:

4 0
4 years ago
An effort of 200 N is used to lift a load of 800 N by using a lever. If the load is at a distance of 40 cm from the fulcrum then
Alchen [17]

The effort distance​ will be 160 cm.Applying the moment at the center as follows will provide the effort distance:

<h3 /><h3>What is the mechanical advantage?</h3>

Mechanical advantage is a measure of the ratio of output force to input force in a system, it is used to obtain the efficiency of forces in levers and pulleys.

Given data;

Effort,\rm F_e=00 N

Load,\rm P= 400 \ N

Distance from the fulcrum,\rm d=40 \ cm

The effort distance​ is found by applying the moment at the center as;

\rm F_e \times d= P \times  d' \\\\ 200 \  N \times d'=800 \ N \times 40 \ cm \\\\ d'=160 \ cm

Hence, the effort distance​ will be 160 cm

To learn more about the mechanical advantage refer to the link;

brainly.com/question/7638820

#SPJ1

7 0
2 years ago
4. The blades on a fan have a frequency of 15 Hz.
vichka [17]

Answer:

a) 4500 cycles b) 0.0667s c) 6.67s

Explanation:

a) 15 Hz= 15 cycles/ s

   5 mins= 300s

   15 cycles/s * 300s= 4500 cycles

b) Period= 1/ frequency

   Period= 1/ 15 cycles/s

   Period= 0.0667s

c) Period * number of revolutions= time

  0.0667 * 100= 6.67s

6 0
3 years ago
Which specialized science would you consult before cultivating your new field or farm for better and profitable yields? A. biote
Zepler [3.9K]
The answer is D soil cience
4 0
3 years ago
Read 2 more answers
30 POINTS!!! I need help ASAP, if someone comments just for points, or is incorrect just for points I will report! Please help!!
Anika [276]

Answer:

1.) answer B

2.) answer D

3.) answer A

Explanation:

In all of these problems, it is essential to draw pictures in order to understand which trigonometric function to use according to the angle that the vector in question forms with the component requested. For all of them try to picture a right angle triangle with the vector as the hypotenuse, and the components as the triangle's shorter sides. Please refer to the three pictures attached as image for this answer a,d notice that the vector quantity known for all cases is represented in red, and the component to find is represented in green.

Problem 1) : the vector velocity makes an angle of 24 degrees with the edge of the table. So picture that vector as the hypotenuse of a right angle triangle for which you know the value: 1.8 m/s

So in this case, where you know the angle, the hypotenuse, and need to find the adjacent side to the angle, you use the cosine function as follows:

requested component =1.8 * cos (24) =1.644 \frac{m}{s}

which we round to 1.6 to match answer C).

For problem 2.) wee need to find the component opposite to the given angle in the triangle for which we also know the hypotenuse. So we use the sine function as follows:

requested component =150 * sin(65) = 135.94 m

which we round to 135.9 m to match answer D).

For problem 3.) we need to find the horizontal component to the acceleration which corresponds to the adjacent side to the known angle, so we use the cosine function as follows:

requested component =12 *cos(50) = 7.71 \frac{m}{s^2}

which we round tp 7.7 to match answer A).

7 0
4 years ago
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