Explanation:
As the given data is as follows.
ohm
,
ohm,
= 1200
(as 1 k ohm = 1000 m)
(a) We will calculate the maximum resistance by combining the given resistances as follows.
Max. Resistance = 
=
ohm
= 2600 ohm
or, = 2.6
ohm
Therefore, the maximum resistance you can obtain by combining these is 2.6
ohm.
(b) Now, the minimum resistance is calculated as follows.
Min. Resistance = 
= 
=
ohm
Hence, we can conclude that minimum resistance you can obtain by combining these is
ohm.
Answer:
Option B. 6.25 J/S
Explanation:
Data obtained from the question include:
t (time) = 2secs
F (force) = 50N
d (distance) = 0.25m
P (power) =?
The power can be obtained by using the formula P = workdone/time.
P = workdone / time
P = (50 x 0.25)/ 2
P = 6.25J/s
Answer:
<em>2.78m/s²</em>
Explanation:
Complete question:
<em>A box is placed on a 30° frictionless incline. What is the acceleration of the box as it slides down the incline when the co-efficient of friction is 0.25?</em>
According to Newton's second law of motion:

Where:
is the coefficient of friction
g is the acceleration due to gravity
Fm is the moving force acting on the body
Ff is the frictional force
m is the mass of the box
a is the acceleration'
Given

Required
acceleration of the box
Substitute the given parameters into the resulting expression above:
Recall that:

9.8sin30 - 0.25(9.8)cos30 = ax
9.8(0.5) - 0.25(9.8)(0.866) = ax
4.9 - 2.1217 = ax
ax = 2.78m/s²
<em>Hence the acceleration of the box as it slides down the incline is 2.78m/s²</em>
Answer:
The time taken for the ball to get to the batter is 0.41 s.
Explanation:
Given;
initial velocity of the baseball, u = 45 m/s
horizontal distance between the pitcher and the batter, X = 18.39 m
The horizontal distance or range of a projectile is given as;
X = ut
where;
t is the time of flight
u is the initial velocity
t = X / u
t = 18.39 / 45
t = 0.41 s
Therefore, the time taken for the ball to get to the batter is 0.41 s.
Answer:
A. You would weigh the same on both planets because their masses and the distance to their centers of gravity are the same.
Explanation:
Given that Planets A and B have the same size, mass.
Let the masses of the planets A and B are and respectively.
As masses are equal, so .
Similarly, let the radii of the planets A and B are and respectively.
As radii are equal, so .
Let my mass is m.
As the weight of any object on the planet is equal to the gravitational force exerted by the planet on the object.
So, my weight on planet A,
my weight of planet B,
By using equations (i) and (ii),
.
So, the weight on both planets is the same because their masses and the distance to their centers of gravity are the same.
Hence, option (A) is correct.