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Gwar [14]
4 years ago
7

3) If an airplane is in flight cruising at constant velocity, what can be said about the net work

Physics
1 answer:
Crazy boy [7]4 years ago
6 0

Explanation:

<h2>Yes!</h2>

<h3>In physics, constant velocity occurs when there is no net force acting on the object causing it to accelerate. In terms of airplane flight, the two main forces influencing its velocity forward are drag and thrust. At a constant altitude, when the force of thrust equals the opposing force of drag, then the airplane will experience uniform motion in one direction. This can be further explained by Newton’s First Law. </h3>
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A book weighs 0.5 kilograms on a book shelf that is 2 meters above the ground. What is the potential energy of the book relative
Elena L [17]
Using the GPE=MGH, M=0.5 kg, G=9.8m/s H= 2 m multiply those all together and we will have 9.8 J (joules)
5 0
3 years ago
Explain the law of conversion of energy with an example and explain it ​
Sophie [7]

Answer:

The law of conservation of energy can be seen in these everyday examples of energy transference: Water can produce electricity. Water falls from the sky, converting potential energy to kinetic energy. ... The cue ball loses energy because the energy it had has been transferred to the 8 ball, so the cue ball slows down.

5 0
3 years ago
Read 2 more answers
Two 3 kg spherical masses are connected by a 20 m long thread of negligible mass that does not stretch. The masses are charged s
Yuri [45]

Answer:

The charge of each sphere is  q = - 1.84 *10^{-4}C

Explanation:

 The  free body diagram of this question is shown on the first uploaded image  

       From the question we are told that

            The mass of the two sphere is m = 3 \ kg

             The length of the connection is l  = 20\ m

              The angle between the suspended side is  \theta = 17 ^o

At Equilibrium the force acting at the horizontal is  = 0N and the net force acting at the vertical is zero

    This can be represented mathematically as

                 \sum F_y = 0N , \ \ and \ \  \sum F_x = 0N

For  \sum F_y = 0N

      T cos \theta = mg

=>     cos \theta  = \frac{mg}{T}

   For  \sum F_x = 0N

        T sin \theta  = F

=>   sin \theta = \frac{F}{T}

     Now  tan \theta  = \frac{sin \theta }{cos \theta }

                       = \frac{\frac{F}{T} }{\frac{mg}{T} }

                       = \frac{F}{mg}                    

Where F is the electrical force which is mathematically represented as

           F = \frac{kq^2}{r^2}

Therefore

           tan \theta = \frac{kq^2}{mgr^2}

 Where r is the distance between the two masses and from the diagram it is

    r = 2l sin \theta

So

      tan \theta = \frac{kq^2 }{(2l sin \theta )^2 * mg}

making q the subject of the formula  

               q = \sqrt{\frac{mg}{k} * tan \theta  (2l sin \theta )^2 }

Where k is  the Coulomb's constant with a value of   k = 9*10^{9} kg \ cdot m^3 s^{-4} A^{-2}

  Substituting values

           q = \sqrt{\frac{3 * 9.8 }{9*10^9} * tan (17) (20 sin 17)^2 }

               q = - 1.84 *10^{-4}C

The negative sign is because we are told from the question that they are negatively charged

                       

           

8 0
3 years ago
Read 2 more answers
. A student claims that if lighting strikes a metal flagpole, the force exerted by the Earth’s magnetic field on the current in
Ratling [72]

Answer:

Explanation:

Given that, current generated from lightning range from

10⁴ A < I < 10^5 A

We know that,

The magnetic force is given as

F = iLB

The magnetic field on the earth surface is

B = 10^-5 T

So, let assume the worst case of a 15m flag pole

L = 15m

Then,

F = iLB

F = 10^5 × 10 × 10^-5

F = 15 N

Therefore, 15N is fairly strong so it will come to the material that was use for the material of the flag pole.

Therefore, it is possible that the student is right depending on the material of the flag pole.

7 0
4 years ago
The mountains would be less steep and more rounded.
3241004551 [841]
The mountains would be less steep and more rounded? What do you mean? I can try to help but you need to give me the question haha
6 0
3 years ago
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