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ss7ja [257]
3 years ago
15

What should I choose?

Chemistry
1 answer:
IrinaK [193]3 years ago
7 0

Answer:

the volume of water with egg was 200 and when we removed the egg become 125

Explanation:

200ml - 125ml = 75ml

so 1 millimeter = 1 centimeter cubic

so

75ml = 75 cm3

the answer is 75cm3

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1. A student wants to test if giving dogs a toy to play with makes their tail wag more. He gives dog toys to one group, while an
WINSTONCH [101]

Answer

Experimental - The Dogs With Toys

Control - The Dogs With No Toys

Explanation - Im smart

5 0
4 years ago
Calculate # of atoms in 46g of Na
makvit [3.9K]

21Explanation:BEACUSE I CAN

5 0
3 years ago
What are the boiling points and freezing points (in oC) of a solution of 50.3 g of I2 in 350 g of chloroform? The kb = 3.63 oC/m
patriot [66]

Answer:

Boiling point: 63.3°C

Freezing point: -66.2°C.

Explanation:

The boiling point of a solution increases regard to boiling point of the pure solvent. In the same way, freezing point decreases regard to pure solvent. The equations are:

<em>Boiling point increasing:</em>

ΔT = kb*m*i

<em>Freezing point depression:</em>

ΔT = kf*m*i

ΔT are the °C that change boiling or freezing point.

m is molality of the solution (moles / kg)

And i is Van't Hoff factor (1 for I₂ in chloroform)

Molality of 50.3g of I₂ in 350g of chloroform is:

50.3g * (1mol / 253.8g) = 0.198 moles in 350g = 0.350kg:

0.198 moles / 0.350kg = 0.566m

Replacing:

<em>Boiling point:</em>

ΔT = kb*m*i

ΔT = 3.63°C/m*0.566m*1

ΔT = 2.1°C

As boiling point of pure substance is 61.2°C, boiling point of the solution is:

61.2°C + 2.1°C = 63.3°C

<em>Freezing point:</em>

ΔT = kf*m*i

ΔT = 4.70°C/m*0.566m*1

ΔT = 2.7°C

As freezing point is -63.5°C, the freezing point of the solution is:

-63.5°C - 2.7°C = -66.2°C

7 0
3 years ago
The first step in the formation of all three products is the loss of the ots leaving group to give a carbocation intermediate. t
lina2011 [118]

The carbocation stabilized by resonance structure and thereby lowers the energy of the carbocation, hydrogen will add to the carbon in the double bond that produces delocalization of electrons.

<h3>What is carbocation?</h3>

A carbocation is a molecule in which a carbon atom has a positive charge and three bonds.

In general, electrons are stabilized by delocalization. The stabilization energy engendered by delocalization over more than two atoms is called the resonance stabilization energy or simply the resonance energy. The greater the extent of electron delocalization the greater the resonance stabilization.

Learn more about the carbocation here:

brainly.com/question/19168427

#SPJ1

4 0
2 years ago
Please help on this one?
Bezzdna [24]

Answer:

\text{C. } _{36}^{85}\text{Kr}

Explanation:

Your nuclear equation is  

_{35}^{85}\text{Br} \longrightarrow \, _{-1}^{0}\text{e} +\, _{x}^{y}\text{X}

The main point to remember in balancing nuclear equations is that

  • the sum of the superscripts and must be the same on each side of the equation.
  • the sum of the subscripts must be the same on each side of the equation.  

Then  

85 = 0 + y, so y = 85 - 0 = 0  

35 = -1 + x, so x = 35 + 1 = 36

The nucleus with atomic number 36 and atomic mass 85 is krypton-85.  

The nuclear equation becomes  

_{35}^{85}\text{Br} \longrightarrow \, _{-1}^{0}\text{e} + \, _{36}^{85}\text{Kr}

4 0
3 years ago
Read 2 more answers
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