Answer:
The current flowing through the 4Ω resistor is;
C. 2.0 A
Explanation:
In the given figure, we have;
The series resistors in the bridge = 8Ω, and 4Ω are in series and 20Ω and 10Ω are in series
The sum of each of the series resistors are;
R₁ = 8Ω + 4Ω = 12Ω
R₂ = 20Ω + 10Ω = 30Ω
The equivalent resistors of the series resistors, R₁ and R₂ are parallel to each other
The current flowing through the 4Ω resistor = The current in R₁ = I₁
By the current divider rule, we have;
Therefore, I₁ = 2.0 A
The current flowing through the 4Ω resistor = I₁ = 2 A
Part A)
Distance is given as sum of total path length
So here as we are given that car drives 40 miles East and 30 miles West
So here the total path length is
Part B)
Displacement is given as straight line distance between initial and final position
So here we can see that
East
West
Now the total displacement will be
<u><em>so the displacement will be 10 miles East</em></u>
Torque is equal position vector times (r) times force vector
(F). Since F= 10 N and r = 0.1 m, so the
torque is equal to (10 N) x ( 0.1 m) = 1Nm. The direction of the torque would
be into the screen, clockwise rotation.
There is strong evidence indicating that 3.8 billion years ago there was a higher impact rate. This deduction starts from comparing the number of craters in the lunar highlands with those of the Mary. If this comparison is made, it will be observed that there are 10 times more craters in the highlands than in a similar area of Mary. It should be borne in mind that through radioactive dating processes the samples indicate that there is a slightly greater antiquity in the highlands than those of Maria. This allows us to deduce that if the impact rates had been constant, the highlands would have been 10 times older. They would have to be formed 38 billion years ago, long before the universe itself began.
Therefore one of the most obvious reasons is there are ten times more craters on the older highlands than the Younger Maria.
Answer:
350 F to 100 F it take approx 87.33 min
Explanation:
given data
oven = 350◦F
cooling rack = 70◦F
time = 30 min
cake = 200◦F
solution
we apply here Newtons law of cooling
= -k(T-Ta)
= (T(t) -Ta)
= = -k(T-Ta)
-ky = -ky
T(t) -Ta = (To -Ta) T(t) = Ta+ (To -Ta)
put her value for time 30 min and T(t) = 200◦F and To =350◦F and Ta = 70◦F
so here
200 = 70 + ( 350 - 70 )
k = 0.025575
so here for T(t) = 100F
100 = 70 + ( 350 - 70 )
time = 87.33 min
so here 350 F to 100 F it take approx 87.33 min