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SpyIntel [72]
3 years ago
7

The direction of the acceleration of an object on a(n) _______________________ path is toward the _______________________ of the

circle.
Physics
1 answer:
melamori03 [73]3 years ago
6 0

Answer:

radial path

center

Explanation:

The direction of the acceleration of an object on a radial path is towards the center of the circle.

This is known as radial acceleration.

  • When a body moves along a circular path, its direction is constantly changing.
  • The acceleration of the body is directed towards the center
  • This is a sort of center seeking motion of a body.
  • It is also known as centripetal acceleration which is drawn towards the middle of the axis.
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kipiarov [429]
Given:
Dy= 20 m
Vi = 5.0 m/s horizontally
A=9.81 m/s^2

Find:
Horizontal displacement

Solution:
D=ViT+(1/2)AT^2
Dy=(1/2)AT^2
T^2=Dy/(1/2)A
T=sqrt(Dy/(1/2)A)
T=sqrt(20/4.905)
T=2.0s

Dx=ViT
Dx=(5.0)(2.0)
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3 years ago
If we connect a third bulb in our series circuit, say one with 4
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Answer:

The current will decrease.

Explanation:

When another bulb is added, the resistance is going to increase. Keep in mind that the current is inversely proportional to the resistance (<em>Ohm's law: R= </em><em>V</em><em>/</em><em>I</em><em> </em><em>).</em> Therefore when the resistance increase, the current running in the circuit will decrease.

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2 years ago
In a classroom, 4 out of every 6 students are female. If there are 27 students, how many of them are female?
icang [17]

Answer:

16 male students, 11 female students

7 0
2 years ago
If two solutions have unequal concentrations of a solute, the solution with the lower concentration is called
marta [7]
Obviouskly lower concentrstion

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3 years ago
From the top of a cliff, a person uses a slingshot to fire a pebble straight downward, which is the negative direction. The init
Talja [164]

Answer:

\vec{a} = -(9.8~{\rm m/s^2})\^y

Explanation:

Regardless of the initial velocity of the pebble, the acceleration of the pebble is equal to the gravitational acceleration which is equal to 9.8 m/s2 towards downwards direction.

This can be shown by Newton's Second Law. According to the law, the net force applied on an object is equal to mass times acceleration of that object.

During the downward motion, the only force acting on the pebble is the gravitational force, hence its acceleration is equal to gravitational acceleration.

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