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sveta [45]
3 years ago
12

A train leaves the station heading south on the tracks. It takes 5 seconds to reach 50 miles per hour. It completes the entire 1

00 mile trip in 2 hours. Calculate the trains average speed and velocity over the two hour trip. Show your work. Identify each of the measurements are a ascalr or vector.
Physics
2 answers:
Musya8 [376]3 years ago
8 0
Well, in order to figure out the answer is to divide until you figure out how many miles they went per second. If it takes 5 seconds to reach 50 miles per hour it took 10 seconds per every 10 miles meaning each mile took 1 second. (Not actually possible but the answer) So, If it finished a 100 mile trip in 2 hours it took an hour for 50 miles. If it took 1 hour for 50 miles divide 60/50 which gets you 1.2 so it took 1.2 miles per minute meaning the car went 120 miles per hour I believe. I hope this helps :)
PilotLPTM [1.2K]3 years ago
4 0

Answer:

Average speed is 50 mph

Average velocity is -50 mph . It is negative since it is towards south.

Explanation:

Distance is a scalar quantity and velocity is a vector. So for a vector, both magnitude and direction should be specified.

Average speed is the total distance over total time taken . So it is 100 miles over 2 hours which gives 50 mph.

Average velocity has the same magnitude and is also 100miles over 2 hours but it is negative since velocity is a vector and it is directed towards south.

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A 20 kg wagon is pulled along the level ground by a rope inclined at 30 degree above the horizontal. A friction force of 30 N op
Elan Coil [88]

(a) 34.6 N

To solve the problem, we have to analyze the forces acting along the horizontal direction.

We have:

- Forward: the component of the pull parallel to the ground, which is

F cos \theta

where

F is the magnitude of the pull

\theta=30^{\circ} is the angle

- Backward: the force of friction, which is

F_f = 30 N

So, the equation of motion is

F cos \theta - F_f = ma

where

m = 20 kg is the mass of the wagon

a is the acceleration

In this part, the wagon is moving at constant speed, so a =0 and the equation becomes

F cos \theta - F_f = 0

Therefore, we can find the pulling force:

F=\frac{F_f}{cos \theta}=\frac{30}{cos 30}=34.6 N

(b) 43.9 N

In this case, the acceleration is

a=0.40 m/s^2

So, the equation of motion in this case is

F cos \theta - F_f = ma

So this time we have to take into account the term (ma).

Using the  same data as before:

m = 20 kg

\theta=30^{\circ}

F_f = 30 N

We find the new magnitude of F:

F=\frac{ma+F_f}{cos \theta}=\frac{(20)(0.40)+30}{cos 30}=43.9 N

6 0
3 years ago
A force that needs to touch something to affect it
bija089 [108]


I would say friction because it requires to surfaces in order for the force to take place

correct me if I'm wrong.

8 0
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marissa [1.9K]

The mechanical energy of the girl will be conserved because the system is isolated and the initial potential energy will be equal to final kinetic energy.

<h3>What is the law of conservation of energy?</h3>

The law of conservation of energy states that energy can neither be created nor destroyed but can be transformed from one form to another.

The change in the potential energy of the  launched from a height into the pool without friction from the given height h is calculated by applying the following kinematic equation.

ΔP.E = ΔK.E

where;

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mghf - mghi = ¹/₂mv²  - ¹/₂mu²

where;

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  • hi is the initial height of the girl
  • hf is the final height when she is launched into the pool
  • u is the initial velocity
  • v is the final velocity of the girl

Thus, for every closed or isolated system such as this case, mechanical energy is always conserved because the initial potential energy of the girl will be converted into her final kinetic energy.

Learn more about conservation of mechanical energy here: brainly.com/question/332163

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The correct answer is A .
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