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sveta [45]
3 years ago
12

A train leaves the station heading south on the tracks. It takes 5 seconds to reach 50 miles per hour. It completes the entire 1

00 mile trip in 2 hours. Calculate the trains average speed and velocity over the two hour trip. Show your work. Identify each of the measurements are a ascalr or vector.
Physics
2 answers:
Musya8 [376]3 years ago
8 0
Well, in order to figure out the answer is to divide until you figure out how many miles they went per second. If it takes 5 seconds to reach 50 miles per hour it took 10 seconds per every 10 miles meaning each mile took 1 second. (Not actually possible but the answer) So, If it finished a 100 mile trip in 2 hours it took an hour for 50 miles. If it took 1 hour for 50 miles divide 60/50 which gets you 1.2 so it took 1.2 miles per minute meaning the car went 120 miles per hour I believe. I hope this helps :)
PilotLPTM [1.2K]3 years ago
4 0

Answer:

Average speed is 50 mph

Average velocity is -50 mph . It is negative since it is towards south.

Explanation:

Distance is a scalar quantity and velocity is a vector. So for a vector, both magnitude and direction should be specified.

Average speed is the total distance over total time taken . So it is 100 miles over 2 hours which gives 50 mph.

Average velocity has the same magnitude and is also 100miles over 2 hours but it is negative since velocity is a vector and it is directed towards south.

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3 years ago
A 180 g model airplane charged to 18 mC and traveling at 2.2 m/s passes within 8.6 cm of a wire, nearly parallel to its path, ca
viva [34]

Answer:

a=0.2*10^{-5}g

Explanation:

From the question we are told that:

Mass M=180=>0.18kg

Charge Q=18mC=18*10^-^3C

Velocity v=2.2m/s

Length of Wire L=8.6cm=>0.086

Current I=30A

Generally the equation for Magnetic Field of Wire B is mathematically given by

 B=\frac{\mu_0*I}{2\pi*l}

 B=\frac{4*3.14*10^-^7*I}{2*3.14*8.6}

 B=6.978*10^{-5}T

Generally the equation for Force on the plane F is mathematically given by

 F=qvB

Therefore

 ma=qvB

 a=\frac{qvB}{m}

 a=\frac{18*10^{-5}83.4*6.978*10^{-5}}{0.18kg}

 a=2.37*10^{-5}

Therefore in Terms of g's

 a=\frac{2.37*10^{-5}}{9.8}

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8 0
3 years ago
8. The mediator particle for gravitational force is on
vodka [1.7K]

Answer:

Gravitone

Explanation:

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6 0
3 years ago
CHEGG You stretch a spring with spring constant k = 1.2x104 N/m to extend 6.0 cm away from its equilibrium position. How much do
lubasha [3.4K]

Answer:

The elastic potential energy of the spring change during this process is 21.6 J.    

Explanation:

Given that,

Spring constant of the spring, k=1.2\times 10^4\ N/m

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We need to find the elastic potential energy of the spring change during this process. The elastic potential energy of the spring is given by the formula as follows :

E=\dfrac{1}{2}kx^2\\\\E=\dfrac{1}{2}\times 1.2\times 10^4\times (0.06)^2\\\\E=21.6\ J

So, the elastic potential energy of the spring change during this process is 21.6 J.

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3 years ago
As in the video, we apply a charge + to the half-shell that carries the electroscope. This time, we also apply a charge – to the
horrorfan [7]

Note: Although the video is not provided in this question, it is not needed to answer the question.

Answer:

B) It does not deflect at all

Explanation:

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