Answer:
2m/s²
Explanation:
acceleration is the rate of change of velocity
for velocity to reach 10m/s in 5s,
acceleration= 10/5
=2
Answer:
120 m
Explanation:
Given:
wavelength 'λ' = 2.4m
pulse width 'τ'= 100T ('T' is the time of one oscillation)
The below inequality express the range of distances to an object that radar can detect
τc/2 < x < Tc/2 ---->eq(1)
Where, τc/2 is the shortest distance
First we'll calculate Frequency 'f' in order to determine time of one oscillation 'T'
f = c/λ (c= speed of light i.e 3 x
m/s)
f= 3 x
/ 2.4
f=1.25 x
hz.
As, T= 1/f
time of one oscillation T= 1/1.25 x
T= 8 x
s
It was given that pulse width 'τ'= 100T
τ= 100 x 8 x
=> 800 x
s
From eq(1), we can conclude that the shortest distance to an object that this radar can detect:
= τc/2 => (800 x
x 3 x
)/2
=120m
(,I hope this helps yoy)
Explanation:
1.If the displacement of an object is zero,the speed must be zero.
Not true
2.(your answer is true)
3.false
4.true
When an electron is accelerated through potential difference then the speed that it attain will be explained by energy conservation
here by energy conservation we can say that
change in kinetic energy of electron = electrostatic potential energy gained through given potential difference
kinetic energy is given as

electrostatic potential energy is given as

now by energy conservation

given that for electron



now by plug in values



So here it is accelerated through potential difference of 2559.4 Volts
Answer:
RT = 17 ohms
Explanation:
For two parallel resistances in a circuit the combined resistance is given by:

R1 = 25 ohms
R2 = 50 ohms
You replace the values of R1 and R2 in the formula for RT:

hence, the combined resitances is 17 ohms