Answer:
The distance covered by the sprinter, s = 40 m
Explanation:
Given data,
The initial velocity of the sprinter, u = 0 m/s
The acceleration of the sprinter, a = 5 m/s²
The time period of acceleration of the sprinter, t = 4 s
Using the II equations of motion
s = ut + ½ at²
= 0 + ½ (5) (4)²
= 40 m
Hence, the distance covered by the sprinter, s = 40 m
1 . W=mass times acceleration due to gravity
60kg times 9.8m/s2
= 588N
2. W=mg
1176N=m times 9.8
m=120kg
3. 1 hour=3600s
24 hours=?
24 times 3600
= 86400 seconds
4. 1000g=1kg
25000g=?
25000 times 1 divide by 1000
=25kg
5. 1000000mg=1kg
123000000=?
123000000 times 1 divide by 1000000
=123 kg
Answer:
Explanation:
The solved solution is on the attach document
Answer: the mutual inductance is - 0.0978H
Explanation:
Detailed explanation and calculation is shown in the image below
820.9 million km thats your answer
