Question

When an aqueous solution of strontium chloride is added to an aqueous solution of potassium sulfate, a precipitation reaction occurs. Write the balanced net ionic equation of the reaction. Include charges on the ions, where applicable. Include coefficients only when they are different than ?

Answer 1

Answer:

$2Cl^{-}_{(aq)} + 2K^{-} _{(aq)} = 2KClx_{(aq)}$

Explanation:

The reaction is a precipitation reaction. In other words, the two aqueous solutions react to give the solid salt, potassium chloride (KCl) in this case.

$SrCl_{2} _{(aq)} + K_{2}SO_{4} _{(s)} = SrSO_{4} _{(aq)} + 2KCl_{(s)}$

Because the reaction product is a solid, the net ionic equation can be written as:

$2Cl^{-}_{(aq)} + 2K^{-} _{(aq)} = 2KClx_{(aq)}$

This is the resultant equation after removing spectator ions: sulfate and strontium.