Answer:
metal ball that moves at high speed
Explanation:
Answer:
igneous rock CAN become sedimentary rock through a process called ROCK CYCLE.
Explanation:
Rocks can be defined as solid structures of minerals that are formed naturally over a period of time. They are grouped into three main types which includes the following:
- igneous rock
- sedimentary rocks and
- metamorphic rocks.
Rocks are capable of transforming from one type to another through a process known as rock cycle. There are two forces that brings about this process which includes:
- The internal force : this is the Earth’s internal heat engine, which moves material around in the core and the mantle and leads to slow but significant changes within the crust.
- The external force: this is the the hydrological cycle, which is the movement of water, ice, and air at the surface, and is powered by the sun.
Molten magma cools to form either extrusive igneous rock or intrusive igneous rock. With time they undergo weathering, eroded, transported, and then deposited as sediments which are being compressed and cemented into SEDIMENTARY ROCKS. Again through the above mentioned forces, different kinds of rocks are either uplifted, to be re-eroded, or buried deeper within the crust where they are heated up, squeezed, and changed into METAMORPHIC ROCK.
Therefore the material in this sedimentary rock found in Rhombus planet used to be in igneous rock deep in Rhombus's interior due to continuous rock cycling on the planet. I hope this helps, thanks.
Answer:
34.23 g.
M = (no. of moles of solute)/(V of the solution (L)).
Answer:
depending on how you change the angle on the ramp the kanetic energy can go up or down depending on how u angle the ramp
Explanation:
Answer:
The new volume is 63583 L
Explanation:
Step 1: Data given
The initial volume of the balloon = 5.37 * 10^4 L
The initial pressure = 0.995 atm
The initial temperature = 32.0 °C = 305.15 K
The pressure decreased to 0.720 atm
The temperature decreased to -11.7 °C = 261.45 K
Step 2: Calculate the new volume
P1*V1 / T1 = P2*V2/T2
⇒with P1 = the initial pressure = 0.995 atm
⇒with V1 = the initial volume = 5.37 *10^4 L
⇒with T1 = the initial temperature = 305.15 K
⇒with P2 = the decreased pressure = 0.720 atm
⇒with V2 = the new volume = TO BE DETERMINED
⇒with T2 = the decreased temperature : 261.45 K
(0.995 * 5.37*10^4)/305.15 = (0.720 * V2) / 261.45
V2 = 63583 L
The new volume is 63583 L
