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LenKa [72]
3 years ago
11

When measuring the volume of an irregularly shaped object you would measure the amount of water____ or pushed away

Chemistry
1 answer:
Over [174]3 years ago
3 0
Displacement is the answer
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In cells, ATP temporarily stores
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Chemical energy obtained from the breakdown of food molecules.

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What if you measured 15cc of liquid elemental mercury, how much would that weigh in pounds
PIT_PIT [208]

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0.447 pounds

Explanation:

The density of Mercury in grams/mL is 13.55 - I multiplied that by the volume and got approximately 203.25 grams, I then turned it into Kilograms and multiplied by 2.2 lbs / kg.

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If faucet drips 5 mL of water each minute, what is the volume of water dripped at the end of five minutes?
kiruha [24]
If the faucet drops at 5 mL per minute you just have to do the following steps to find out.

5 mL for the dripping rate times 5 for the minutes.

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When electrons are added to the outer most shell of a carbon atom what does it form
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3 0
3 years ago
Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calcu
stealth61 [152]

Answer:

Explanation:

Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calculate the value of the rate constant at 25 °C. Alternatively, you can simply extrapolate the straight line plot of ln(k) vs. 1/T in your notebook to 1/298 , read off the value of ln(k), and determine the value of k. Please put your answer in scientific notation. slope=-12070, Ea=100kJ/mol, k= 0.000717(45C), 0.00284(55C), 0.00492(65C), 0.0165(75C), 0.0396(85C)

Explanation;

According to Arrhenius equation:

i.e. ln(k2/k1) = -Ea/R (1/T2 - 1/T1)

Where, k1 = 0.000717, T1 = 45 oC = (45+273) K = 318 K

T2 = 25 oC = (25 + 273) K = 298 K

i.e. ln(k2/0.000717) = -12070 (1/298 - 1/318)

i.e. ln(k2/0.000717) = -2.54738

i.e. k2/0.000717 = e^{-2.54738}

= 0.078286

Therefore, the required constant (k2) = 0.078286 * 0.000717 = 5.61*10^-^5

6 0
3 years ago
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