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2 years ago

How do elements heavier than iron form?

Chemistry

1 answer:

Vilka [71]2 years ago

4 0

Answer:

<h2>neutron capture </h2>

Explanation:

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Calculate the ratio of the mass ratio of SS to OO in SOSO to the mass ratio of SS to OO in SO2SO2. Consider a sample of SOSO in

Veronika [31]

Answer:

The ratio of the mass ratio of S to O; in SO, to the mass ratio of S to O; in SO₂, is 2:1

Explanation:

According to the consideration, let us first find the ratio of S and O in both the compounds

For SO:

$\frac{m_{S} }{m_{O} }= \frac{32}{16}\\\\ \frac{m_{S} }{m_{O} }= 2$

Let us express it as

$SO_{\frac{m_{S} }{m_{O} }} = 2$

For SO₂,

Due to two oxygen atoms in the molecule, the mass of oxygen will be taken two times

$\frac{m_{S} }{m_{O} }= \frac{32}{(2)(16)}\\\\ \frac{m_{S} }{m_{O} }= 1$

Let us express it as

$SO_2_{\frac{m_{S} }{m_{O} }}= 1$

Now, for the ratio of both the above-calculated ratios,

$\frac{SO_{\frac{m_{S} }{m_{O} }}}{SO_2_{\frac{m_{S} }{m_{O} }}}=\frac{2}{1}$

The required ratio is 2:1

3 0

3 years ago

To protect itself from herbivores, plants ______

9966 [12]

C.) both secrete toxins and have thorns (It simply depends on what kind of plant it is)

3 0

3 years ago

Read 2 more answers

What charge does a proton have

Nata [24]

It has a positive charge of 1

5 0

3 years ago

Which functional group does the molecule below have?

makvit [3.9K]

Answer:

Explanation:

7 0

2 years ago

"benzyl ethyl ether reacts with concentrated aqueous hi to form two initial organic products (a and b). further reaction of prod

ahrayia [7]

Answer:

See below.

Step-by-step explanation:

Ethers react with HI at high temperature to produce an alky halide and an alcohol.

R-OR' + HI ⟶ R-I + H-OR'

Benzylic ethers react by an Sₙ1 mechanism by forming the stable benzyl cation.

PhCH₂-OR + HI ⟶ PhCH₂-O⁺(H)R + I⁻ Protonation of the ether
PhCH₂-O⁺(H)R ⟶ PhCH₂⁺ + HOR Sₙ1 ionization of oxonium ion
PhCH₂⁺ + I⁻ ⟶ PhCH₂-I Nucleophilic attack by I⁻

If there is excess HI, the alcohol formed in Step 2 is also converted to an alkyl iodide:

ROH +HI ⟶ R-I + H-OH

Thus, benzyl ethyl ether reacts to form benzyl iodide (a) and ethanol (b).

The ethanol reacts with excess HI in an Sₙ2 reaction to form ethyl iodide (c).

4 0

3 years ago