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astra-53 [7]
3 years ago
15

Is time real If everything is relative to gravity

Physics
1 answer:
kozerog [31]3 years ago
4 0

Answer: yes time is real because though everything is relative to gravity they mean material things while time isn't a material thing making it different from gravity and leaving it as its own entity.

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How are we able to break wire by repeated bending​
Arlecino [84]

Answer:

We are able to break it because wire is elastic which means that it stretches. The more we stretch it the more the material comes off.

Explanation:

6 0
3 years ago
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Uranus has more than 14 times as much mass as earth, yet the gravitational force is less. how can that be?
Anarel [89]
It has more mass, yes. But it has less of a gravitational pull because it is farther away from the sun than the Earth is
3 0
3 years ago
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How much kinetic energy does a baseball with a mass of 0.143 kg have it it is traveling at a velocity of 41.1 m/s?
vampirchik [111]

Answer:

E = 120.77 J

Explanation:

Given that,

Mass of a baseball, m = 0.143 kg

Velocity of a baseball, v = 41.1 m/s

We need to find the kinetic energy of the baseball. We know that the kinetic energy of an object is associated with its motion. It can be given by the formula as follow :

E=\dfrac{1}{2}mv^2\\\\E=\dfrac{1}{2}\times 0.143\ kg\times (41.1\ m/s)^2\\E=120.77\ J

So, the kinetic energy of the baseball is 120.77 J.

3 0
3 years ago
3. In a physics lab, 0.500-kg cart (Cart A) moving rightward with a speed of 100 m/s collides with a 1.50-kg cart (Cart B) movin
Alex787 [66]

Answer:

The speed of the two carts after the collision is 10 m/s.

Explanation:

Hi there!

The momentum of the system Cart A - Cart B is conserved because there is no external force acting on the system at the instant of the collision. Then, the momentum of the system before the collision will be equal to the momentum of the system after the collision. The momentum of the system is calculated as the sum of momenta of cart A and cart B:

initial momentum = mA · vA1 + mB · vB1

final momentum = (mA + mB) · vAB2

Where:

mA = mass of cart A = 0.500 kg

vA1 = velocity of cart A before the collision = 100 m/s

mB = mass of cart B = 1.50 kg.

vB1 = velocity of cart B before the collision = - 20 m/s

vAB2 = velocity of the carts that move as a single object = unknown.

(notice that we have considered leftward as negative direction)

Since the momentum of system remains constant:

initial momentum = final momentum

mA · vA1 + mB · vB1 = (mA + mB) · vAB2

Solving for vAB2:

(mA · vA1 + mB · vB1) / (mA + mB) = vAB2

(0.500 kg · 100 m/s - 1.50 kg · 20 m/s) / (0.500 kg + 1.50 kg) = vAB2

vAB2 = 10 m/s

The speed of the two carts after the collision is 10 m/s.

6 0
3 years ago
Two objects, one of mass m and the other of mass 2m, are dropped from the top of a building. when they hit the ground
Setler79 [48]
They will both hit the ground at the same time because gravitational acceleration for all objects is the same.
6 0
3 years ago
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