Unlike credit card purchases, interest charged on cash advances is already incurred even if you pay before the due date.
32% is the annual interest rate
1 month is the term
200 is the principal
32% / 12 months = 2.67% per month
200 * 2.67% = 5.34 monthly interest
200 * 32% = 64 annual interest
64/12 = 5.33 monthly interest
She has to pay $5.34 in interes
Answer:
3x-2y=17........(1)
x=4y-1
substituting value of x in equation 1
3(4y-1)-2y=17
12y-3-2y=17
10y=17+3
y=20/10=2
again
substituting value of y in equation 1
3x-2×2=17
3x=17+4
x=21/3=7
:.x=7,y=2
Answer:
Add 7 to both sides
Step-by-step explanation:
The equation has to be just x = y
There cannot be another number on the same side as the variable
Now that we did that, the equation is 9x = 0
x = 0
Well, that was easy lol
Answer:
1120 yards cubed
Step-by-step explanation:
hope this helps
have a good day
Answer:
The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.
This means that 
80% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).