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3 years ago

9

What are the period and group trends in electronegativities

1 answer:

Leviafan [203]3 years ago

8 0

Electronegativity of an element decreases as we move down a group on the periodic table and electronegativity increases while moving from left to right across a period on the periodic table.

Explanation:

The electronegativity increases as we move from left to right across a period because from left to right across a period, the nuclear charge is increasing Hence the attraction for the valence electrons also increases.
As we move down a group, the atoms of each element have an increasing number of energy levels. The distance between the nucleus and valence electron shell increases and reduces the attraction for valence electrons. Hence electronegativity decreases as we move from top to bottom down a group.

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What are the coefficients for the following reaction when it is properly balanced? ?potassium iodide +?lead (II) acetate lead (I

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Answer: none of the above

Explanation:

It should be 2,1,1,2 to give a balanced chemical reaction

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3 years ago

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Answer:

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2 years ago

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Following the instructions in your lab manual, you have titrated a 25.00 mL sample of 0.0100 M KIO3 with a solution of Na2S2O3 o

vivado [14]

<u>Answer:</u>

<u>For 1:</u> The amount of potassium iodate that were titrated is $2.5\times 10^{-4}$ moles

<u>For 2:</u> The amount of sodium thiosulfate required is $1.25\times 10^{-4}$ moles

<u>Explanation:</u>

<u>For 1:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}$

Molarity of $KIO_3$ solution = 0.0100 M

Volume of solution = 25 mL

Putting values in above equation, we get:

$0.0100M=\frac{\text{Moles of }KIO_3\times 1000}{25}\\\\\text{Moles of }KIO_3=\frac{0.0100\times 25}{1000}=0.00025mol$

Hence, the amount of potassium iodate that were titrated is $2.5\times 10^{-4}$ moles

<u>For 2:</u>

The chemical equation for the reaction of potassium iodate and sodium thiosulfate follows:

$2KIO_3+Na_2S_2O_3\rightarrow K_2S_2O_3+2NaIO_3$

By Stoichiometry of the reaction:

2 moles of potassium iodate reacts with 1 mole of sodium thiosulfate

So, 0.00025 moles of potassium iodate will react with = $\frac{1}{2}\times 0.00025=0.000125mol$ of sodium thiosulfate

Hence, the amount of sodium thiosulfate required is $1.25\times 10^{-4}$ moles

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3 years ago

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zalisa [80]

Some chemical changes can be reactive through another chemical change?

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2 years ago