We can write the balanced equation for the synthesis reaction as
H2(g) + Cl2(g) → 2HCl(g)
We use the molar masses of hydrogen chloride gas HCl and hydrogen gas H2 to calculate for the mass of hydrogen gas H2 needed:
mass of H2 = 146.4 g HCl *(1 mol HCl / 36.46 g HCl) * (1 mol H2 / 2 mol HCl) *
(2.02 g H2 / 1 mol H2)
= 4.056 g H2
We also use the molar masses of hydrogen chloride gas HCl and chlorine gas CL2 to calculate for the mass of hydrogen gas H2:
mass of CL2 = 146.4 g HCl *(1 mol HCl / 36.46 g HCl) * (1 mol Cl2 / 2 mol HCl) *
(70.91 g Cl2 / 1 mol Cl2)
= 142.4 g Cl2
Therefore, we need 4.056 grams of hydrogen gas and 142.4 grams of chlorine gas to produce 146.4 grams of hydrogen chloride gas.
Reactants are the substances that undergo changes and the new substance created from it is called products.
Since there's specific heat, you should use Q=mc△T. Depends on if this question also involves phase change or not, you might will need Lf (latent heat of fusion) or Lv (latent heat of vaporisation).
N₂O₄ (g) ⇌ 2 NO₂ (g)
Kc = [ NO₂ ]² / [ N₂O₄ ]
4.2 = [ 0.785 ] [ N₂O₄ ]
[ N₂O₄ ] = 4.2 / 0.785
[N₂O₄ ] = 5.350 M
hope this helps!
Answer:
3.45 moles Li contains 2.08 × 10 (to the power of)24 atoms .
Explanation:
The relationship between atoms and moles is:
1 mole atoms =
6.022 × 10 (to the power of)23
atoms
In order to determine how many atoms occupy a given number of moles, multiply the given moles by
6.022 × 10 (to the power of)23
atoms/mole
.
In the case of 3.45 moles lithium (Li):
3.45 mol Li × 6.022 × 10 (to the power of)23 atoms Li/ 1 mol Li =
2.08 × 10 (to the power of)24
atoms Li rounded to three
