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3 years ago

Use the dropdown to create a unbalanced diagram with the dog using Applied Force pulling to the right.

Chemistry

1 answer:

Ber [7]3 years ago

7 0

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The titration of a 20.0-mLmL sample of an H2SO4H2SO4 solution of unknown concentration requires 22.87 mLmL of a 0.158 M KOHM KOH

kkurt [141]

Answer:

0.0905 M

Explanation:

Let's consider the neutralization reaction between H2SO4 and KOH.

H₂SO₄ + 2 KOH → K₂SO₄ + 2 H₂O

22.87 mL of 0.158 M KOH react. The reacting moles of KOH are:

0.02287 L × 0.158 mol/L = 3.61 × 10⁻³ mol

The molar ratio of H₂SO₄ to KOH is 1:2. The reacting moles of H₂SO₄ are 1/2 × 3.61 × 10⁻³ mol = 1.81 × 10⁻³ mol

1.81 × 10⁻³ moles of H₂SO₄ are in 20.0 mL. The molarity of H₂SO₄ is:

M = 1.81 × 10⁻³ mol / 0.0200 L = 0.0905 M

3 0

2 years ago

6.) The bond between which two atoms is most polar?*

Feliz [49]

Answer:

O-H bond

Explanation:

Let us work out the electronegativity difference between the elements in each bond in order to decide which of them is most polar.

For the C-O bond

2.55 - 2.2 =0.35

For the F-F bond

3.98 - 3.98 = 0

For the O-H bond

3.44 - 2.2 = 1.24

For the N-H bond

3.04 - 2.2 = 0.84

The O-H bond has the highest electronegativity difference, hence it is he most polar bond.

4 0

2 years ago

What was the answer \

bearhunter [10]

What was the question?

4 0

2 years ago

Ok this is so weird but like how do you expose fake friends for talking about you? I know they did it but i dont know how to tal

murzikaleks [220]

Answer:

just do it

Explanation:

8 0

3 years ago

Read 2 more answers

(c) O2 gas is transferred from a 3 L vessel containing oxygen at 4 atm to an evacuated 20 L vessel at a constant temperature of

Fudgin [204]

Answer:

After the transfer the pressure inside the 20 L vessel is 0.6 atm.

Explanation:

Considering O2 as an ideal gas, it is at an initial state (1) with V1 = 3L and P1 = 4 atm. And a final state (2) with V2 = 20L. The temperature remain constant at all the process, thus here applies the Boyle-Mariotte law. This law establishes that at a constant temperature an ideal gas the relationship between pressure and volume remain constant at all time:

$P x V = k$

Therefore, for this problem the step by step explanation is:

$P_{1} xV_{1} = P_{2} xV_{2}$

Clearing P2 and replacing

$P_{2}= \frac{P_{1} xV_{1}}{V_{2} } = \frac{4atmx3L}{20L} = 0.6atm$

7 0

3 years ago