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Allushta [10]
3 years ago
13

A gold coin contains 3.47 × 10^23 gold atoms. What is the mass of the coin in grams?

Chemistry
1 answer:
VashaNatasha [74]3 years ago
4 0

Answer:

Mass = 114.26 g

Explanation:

Given data:

Number of gold atoms = 3.47×10²³ atoms

Mass in gram = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.  The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ atoms

3.47×10²³ atoms × 1 mol  /6.022 × 10²³ atoms

0.58 mol

Mass of gold:

Mass = number of moles × molar mass

Mass = 0.58 mol × 197 g/mol

Mass = 114.26 g

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If δh = -70.0 kj and δs = -0.500 kj/k , the reaction is spontaneous below a certain temperature. calculate that temperature. exp
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A 100g sample of Carbon-14 has a half-life of 5 years. How much Carbon-14 is left after 10 years?
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Explanation:

Formula used :

a=\frac{a_o}{2^n}

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