<h2>Hello!</h2>
The answer is: 19.59 m
<h2>Why?</h2>
Since there is no information about the launch type, we can assume that the ball is thrown vertically upward.
When the ball reaches the maximum height, just at that moment, the velocity turns to 0, and after that moment, the ball starts falling, so:
We will use the following formula:

Where:
Vf= Final velocity = 0
Vi= Initial velocity = 
g = Gravity Acceleration = 
s = Traveled distance

Have a nice day!
Answer:
since they have got specific and special metallic and non metallic characteristics I guess
When you are talking about calculating the kinetic energy of an object, the formula is as stated:
Ek =1/2mv²
Where m is mass and v is velocity. Sub all those numbers in and you'll get 25J of kinetic energy.
Average v = (initial v + final v)/2
= (14 m/s + 0 m/s)/2
= 7 m/s
Your average velocity during braking is 7 m/s