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Yuki888 [10]
3 years ago
12

During a spontaneous chemical reaction, it is found that ΔSsys is less than 0. This means that Group of answer choices ΔSsurr is

less than 0 and its magnitude is less than ΔSsys. ΔSsurr is less than 0 and its magnitude is greater than ΔSsys. ΔSsurr is greater than 0 and its magnitude is less than ΔSsys. ΔSsurr is greater than 0 and its magnitude is greater than ΔSsys. an error has been made, as Ssys is greater than 0 by necessity for a spontaneous process.
Chemistry
1 answer:
Evgen [1.6K]3 years ago
3 0

Answer:

The correct option is: ΔSsurr is greater than 0 and its magnitude is greater than ΔSsys.  

Explanation:

For a <u>chemical reaction to be spontaneous, the change in the</u> <u>Gibbs free energy should be negative (ΔG = -ve).</u>

At constant temperature (T) and pressure, the Gibbs free energy is given by the equation: \Delta G_{system} = \Delta H_{system} - T\Delta S_{system}

Here, \Delta H_{system} is the enthalpy change and \Delta S_{system} is the entropy change of the system.

Also, <u>according to the second law of thermodynamics</u>, <u>for a spontaneous process, the total entropy</u>, \Delta S_{universe} = \Delta S_{system} + \Delta S_{surrounding} > 0

Therefore, <u>for a reaction to be spontaneous</u>, if \Delta S_{system} is less than 0 or negative; then <u>\Delta S_{surrounding} should be greater than 0 or positive. </u>Also, \Delta S_{surrounding} > \Delta S_{system}.

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<h3>Further explanation   </h3>

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