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alexandr1967 [171]
3 years ago
11

Why is the answer C?

Physics
1 answer:
4vir4ik [10]3 years ago
7 0

Explanation:

We want to find the statement that is proven by the fact that the balls reach the same height.

A isn't supported by the evidence.  Balls can reach the same height without having the same initial speed.

B isn't supported by the evidence.  Balls can reach the same height without having the same launch angle.

C is supported.  Projectiles spend the same amount of time going up as they do coming down, so if two projectiles reach the same height, then they must spend the same amount of time in the air.

D isn't supported by the evidence.  Balls thrown at the same speed and complementary angles have the same range but different heights.

E isn't supported by the evidence.  The mass of the ball doesn't affect the height.

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A 0.30-kg object connected to a light spring with a force constant of 22.6 N/m oscillates on a frictionless horizontal surface.
gtnhenbr [62]

Answer:

(a)  vmax = 0.34m/s

(b)  v = 0.13m/s

(c)  v = 0.31m/s

(d)  x = 0.039m

Explanation:

Given information about the spring-mass system:

m: mass of the object = 0.30kg

k: spring constant = 22.6 N/m

A: amplitude of the motion = 4.0cm = 0.04m

(a) The maximum speed of the object is given by the following formula:

v_{max}=\omega A       (1)

w: angular frequency of the motion.

The angular frequency is calculated with the following relation:

\omega=\sqrt{\frac{k}{m}}           (2)

You replace the expression (2) into the equation (1) and replace the values of the parameters:

v_{max}=\sqrt{\frac{k}{m}}A=\sqrt{\frac{22.6N/m}{0.30kg}}(0.04m)=0.34\frac{m}{s}

The maximum speed of the object is 0.34 m/s

(b) If the object is compressed 1.5cm the amplitude of its motion is A = 0.015m, and the maximum speed is:

v_{max}=\sqrt{\frac{22.6N/m}{0.30kg}}(0.015m)=0.13\frac{m}{s}

The speed is 0.13m/s

(c) To find the speed of the object when it passes the point x=1.5cm, you first take into account the equation of motion:

x=Acos(\omega t)

You solve the previous equation for t:

t=\frac{1}{\omega}cos^{-1}(\frac{x}{A})\\\\\omega=\sqrt{\frac{22.6N/m}{0.30kg}}=8.67\frac{rad}{s}\\\\t=\frac{1}{8.67}cos^{-1}(\frac{1.5cm}{4.0cm})=0.13s

With this value of t, you can calculate the speed of the object with the following formula:

v=\omega Asin(\omega t)\\\\v=(8.67rad/s)(0.04m)sin((8.67rad/s)(0.13s))=0.31\frac{m}{s}

The speed of the object for x = 1.5cm is v = 0.31 m/s

(d) To calculate the values of x on which v is one-half the maximum speed, you first calculate the time t:

\frac{v_{max}}{2}=\omega A sin(\omega t)\\\\t=\frac{1}{\omega}sin^{-1}(\frac{v_{max}}{2\omega A})\\\\t=\frac{1}{8.67rad/s}sin^{-1}(\frac{0.13m/s}{2(8.67rad/s)(0.04m)})=0.021s

The position will be:

x=Acos(\omega t)=0.04mcos((8.67rad/s)(0.021s))=0.039m

The position of the object on which its speed is one-half its maximum velocity is 0.039

5 0
3 years ago
How many days sun rises in a year​
Lana71 [14]

Answer:

365

Explanation:

there are 365 days in a year

8 0
3 years ago
Is it true that if an object is moving it has kinetic energy
densk [106]
Yes an object in motion has kinetic energy
5 0
3 years ago
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Suppose you know a golf ball’s horizontal velocity (Vx) and the time it had traveled through the air (t). How could you calculat
alex41 [277]

Answer:

The answer is "distance = Vx × t"

Explanation:

To determine how far the golf ball traveled, the formula for velocity can be used, which is

velocity (m/s) = distance (m) ÷ time (s)

Make distance the subject of the formula

distance = velocity × time

Thus, where velocity is Vx and time is t

distance = Vx × t

The unit of the distance will be in meter (m)

8 0
2 years ago
How much energy is contained in matter with a mass of 1 gram (0,001 kilogram)?
AnnZ [28]

Answer:

1 gram of matter contains: 299,792,458^2=8.99 x 10^13 Joules=~21,500 Tons of TNT explosives, which is almost exactly the size of the atomic bomb dropped on Nagasaki in WW2. Guest May 17, 2016 #2

Hope this helped!

Explanation:

7 0
2 years ago
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