The amplitude of a standing sound wave in a long pipe closed at the left end is sketched below. The vertical axis is the maximum
1 answer:
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Answer:
a-1 Graph is attached. The relation is linear.
a-2 The corresponding height for 68 kPa Pressure is 7.54 m
a-3 The corresponding weight for 68 kPa Pressure is 1394726kg
b The original height of the column is 5.98 m
Explanation:
Part a
a-1
The graph is attached with the solution. The relation is linear as indicated by the line.
a-2
By the equation
Here
- P is the pressure which is given as 68 kPa.
- ρ is the density of the oil whose SG is 0.92. It is calculated as
- g is the gravitational constant whose value is 9.8 m/s^2
- h is the height which is to be calculated
So the height of column is 7.54m
a-3
By the relation of volume and density
Here
- ρ is the density of the oil which is 920 kg/m^3
- V is the volume of cylinder with diameter 16m calculated as follows
Mass is given as
So the mass of oil leading to 68kPa is 1394726kg
Part b
Pressure variation is given as
Now corrected pressure is as
Finding the value of height for this corrected pressure as
The original height of column is 5.98m
Answer:
the tangential velocity of the student is 4.89 m/s.
Explanation:
Given;
the radius of the circular path, r = 3.5 m
duration of the motion, t = 4.5 s
let the student's tangential velocity = v
The tangential velocity of the student is calculated as follows;
Therefore, the tangential velocity of the student is 4.89 m/s.