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3 years ago

When practicing deep breathing, it is best to repeat the steps for

Physics

2 answers:

GrogVix [38]3 years ago

8 0

Answer:

c.) 10 to 15 minutes

Explanation:

Alborosie3 years ago

6 0

Answer:

c.) 10 to 15 minutes

Explanation:

yw :)

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What is a property of “normal force”? a. It always points perpendicular to the contact surface. b. It always points parallel to

OleMash [197]

Answer:

a. It always points perpendicular to the contact surface.

Explanation:

"Normal" means perpendicular. Normal forces are always perpendicular to the contact surface.

6 0

3 years ago

What the 3 law of newton mean

Masteriza [31]

Newtons third law of motion states that for every action, there is an equal an opposite reaction. This means that the force on back on something is going to be equal in size and opposite in direction.

3 0

3 years ago

The correct equation for the x component of a vector named A with an angle measured from the x axis would be which of the follow

Lady_Fox [76]

Answer:

Acosθ

Explanation:

The x-component of a vector is defined as :

Magnitude * cosine of the angle

Maginitude * cosθ

The magnitude is represented as A

Hence, horizontal, x - component of the vector is :

Acosθ

Furthermore,

The y-component is taken as the sin of the of the angle multiplied by the magnitude

Vertical, y component : Asinθ

8 0

3 years ago

Salmon often jump waterfalls to reach their breeding grounds. Starting downstream, 3.18 m away from a waterfall 0.294 m in heigh

Karolina [17]

Answer:

v = 7.65 m/s

t = 0.5882 s

Explanation:

We are told that the salmon started downstream, 3.18 m away from a waterfall.

Thus, range = 3.18 m

Since the horizontal velocity component is constant, then;

Range = vcosθ × t

Thus,

vcosθ × t = 3.18 - - - (eq 1)

We are told the salmon reached a height of 0.294 m

Thus, using distance equation;

s = v_y•t + ½gt²

g will be negative since motion is against gravity.

s = v_y•t - ½gt²

Thus;

0.294 = v_y•t - ½gt²

v_y = vsinθ

Thus;

0.294 = vtsinθ - ½gt² - - - (eq 2)

From eq(1), making v the subject, we have;

v = 3.18/tcosθ

Plugging into eq 2,we have;

0.294 = (3.18/tcosθ)tsinθ - ½gt²

0.295 = 3.18tanθ - ½gt²

We are given g = 9.81 m/s² and θ = 45°

0.295 = (3.18 × tan 45) - ½(9.81) × t²

0.295 = 3.18 - 4.905t²

3.18 - 0.295 = 4.905t²

4.905t² = 2.885

t = √2.885/4.905

t = 0.5882 s

Thus;

v = 3.18/(0.5882 × cos45)

v = 7.65 m/s

8 0

3 years ago

A cart is rolling across the floor at a constant velocity of 2 m/s to the right. The cart is pushed again to the right, and it s

OlgaM077 [116]

The force of the push and acceleration of the cart are related such as The unbalanced push causes the cart to accelerate.

4 0

3 years ago