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qaws [65]
3 years ago
15

What is the volume of a stopper that has a mass of 57 grams and a density of 8.4 g/cm3?

Physics
1 answer:
nikdorinn [45]3 years ago
8 0

Answer:

Explanation:

Mass ( m) = 57 gram

density (d)= 8.4 g/cm^3

volume (v)=?

we know density is mass per unit volume

d = m/v

or v = m/d

v = 57/ 8.4

volume = 6.79 cm^3

hOPe it will help :)

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The Force per meter on a straight wire carrying current in a magnetic field is<u>  0.045 N/m.</u>

<u>Calculation:-</u>

       F/ℓ = B I sin θ

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Substituting the values

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If you could travel at the speed of light, how long would it take to travel from our solar
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If two stars are the same size and one is twice the temperature of the other, how much more luminous is the hotter one? quizlit
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A diagram of a closed circuit with a power source on the left labeled 120 V. There are 3 resistors in parallel, separate paths,
Zina [86]

1) The equivalent resistance is 2.73\Omega

2) The voltage in the circuit is 120 V

3) The total current in the circuit is 44.0 A

Explanation:

1)

Resistors are said to be in parallel when they have the same potential difference at their terminals.

The formula to calculate the equivalent resistance for three resistors in parallel is:

\frac{1}{R_T}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}

where R_1, R_2, R_3 are the resistances of the three resistors.

In this problem, the resistance of each resistor is:

R_1 = 5.0 \Omega

R_2 = 10.0 \Omega

R_3 = 15.0 \Omega

Substituting,

\frac{1}{R_T}=\frac{1}{5}+\frac{1}{10}+\frac{1}{15}=\frac{11}{30}

So the equivalent resistance is

R_T = \frac{30}{11}=2.73 \Omega

2)

In this problem we are told that the three resistors are connected in parallel. This means that their terminals are connected to the same point of the circuit: therefore, this means that they also have the same potential difference across them.

Therefore, the voltage in each branch containing each resistor is the same, and it is equal to the voltage of the battery, which is

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3)

The total current in the circuit can be found by using Ohm's law:

V=RI

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V is the voltage

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In this circuit, we have:

V = 120 V

R=2.73\Omega

Re-arranging the equation for I, we find the current:

I=\frac{V}{R}=\frac{120}{2.73}=44.0 A

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