1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dennis_Churaev [7]
3 years ago
6

(SCIENCE) 22 POINTS AND CROWN ASAP

Physics
1 answer:
gayaneshka [121]3 years ago
5 0

Answer:

A or D

Explanation:

Net force includes addition or subtraction.

You might be interested in
Si pudieras viajar a la Luna:
Nostrana [21]

Answer:

i) Distancia, ii) La cinta métrica es impracticable.

Explanation:

i) El concepto físico que se construye únicamente del punto de salida y el punto de llegada a la Luna es el concepto de desplazamiento, definido como la distancia en línea recta de un punto en el espacio con respecto a un punto de referencia (la Tierra en este caso).

La distancia puede involucrar trayectorias curvilíneas entre los puntos mencionados.

ii) Por último, el uso de una cinta métrica es impracticable debido a la cantidad de material a utilizar y los efectos gravitacionales, electromagnéticos y mecánicos que inducen a una deflexión o una ruptura de esa cinta debido a la magnitud de la distancia entre las superficies del planeta y el satélite, respectivamente.

En este caso, es mejor utilizar la medición con tecnología láser, basadas en el fenómeno del electromagnetismo.

4 0
3 years ago
What is Newton's 2nd law of motion? *<br> Your answer
Novay_Z [31]
Acceleration of an object is depended upon the net force acting open the object and the mass of the object
4 0
2 years ago
Read 2 more answers
Momentum and different surfaces
saw5 [17]
What are you asking here?
5 0
3 years ago
At a certain instant an object is moving to the right with speed 1.0 m/s and has a constant acceleration to the left of 1.0 m/s2
professor190 [17]

Explanation:

Given that,

Initial speed of the object, u = 1 m/s

Acceleration of the object, a=-1\ m/s^2

We need to find the time when the object comes at rest (v=0). Let it is given by :

t=\dfrac{v-u}{a}

t=\dfrac{0-1\ m/s}{-1\ m/s^2}

t = 1 second

So, the object will comes to rest at 1 second. Hence, this is the required solution.

5 0
3 years ago
g An arrow is shot straight up in the air at an initial speed of 15.5 m/s. After how much time is the arrow moving downward at a
Sati [7]

Answer:

2.11 seconds

Explanation:

We use the kinematic equation for the velocity in a constantly accelerated motion under the acceleration of gravity (g):

v_f=v_i-g*t\\-5.2 = 15.5 - 9.8\,t\\9.8 \,t= 15.5 + 5.2\\t = 20.7/9.8\\t = 2.11 \,\,sec

5 0
3 years ago
Other questions:
  • A rock of mass 200kg is dropped from a height of 200m. What is the Kinetic energy at:
    14·2 answers
  • Plane 1 leaves city A at 7 am and flies at a speed of 250 mph in a straight line towards city B, located 1000 miles North of cit
    8·1 answer
  • The wavelength of red helium-neon laser light in air is 632.8 nm.(a) What is its frequency?(b) What is its wavelength in glass t
    6·1 answer
  • If a microwave oven produces electromagnetic waves with a frequency of 2.70 ghz, what is their wavelength?
    13·1 answer
  • WILL GIVE BRAINLIEST AND 50 POINTS!
    14·2 answers
  • The position of an object in simple harmonic motion is described by the following equation: y=(0.50 m)cos(pi/2)t. What is the am
    5·2 answers
  • Which has more kinetic energy, a basketball rolling at a walking pace or a baseball rolling at the pace of someone running? How
    12·1 answer
  • An object is traveling at a velocity of 100 rn/s to the left for about 5 seconds. How far has the object traveled? (What is the
    8·1 answer
  • Sir Percival and his horse are standing still on a field of honor when Sir Rodney, atop his steed gallops by with a constant vel
    12·1 answer
  • a. 2.00kg object is subject to three force that gives acceleration a =8m/s^2 i +6m/s j if two of three forces are f1 =(30.0N)+(1
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!