All categories

2 years ago

(SCIENCE) 22 POINTS AND CROWN ASAP

Physics

1 answer:

gayaneshka [121]2 years ago

5 0

Answer:

A or D

Explanation:

Net force includes addition or subtraction.

You might be interested in

You're driving a bumper car at a circus at

Jlenok [28]

Answer:

PLEASE MARK AS BRAINLIEST!!

Explanation:

ANSWER IS IN THE IMG BELOW

4 0

2 years ago

Consider the uniform electric field \vec{E} =(4.00~\hat{j}+3.00~\hat{k})\times 10^3~\text{N/C} E ⃗ =(4.00 j ^ +3.00 k

Tema [17]

Answer:

Electric flux, $\phi=6.668\times 10^4\ Nm^2/C$

Explanation:

It is given that,

Electric field, $E=(4j+3k)\times 10^3\ N/C$

We need to find the electric flux through a circular area of radius 2.66 m that lies in the xy-plane. $A=Ak$

The electric flux is given by :

$\phi=E{\cdot}A$

$\phi=(4j+3k)\times 10^3{\cdot}Ak$

Since, k.k=i.i=j.j = 1

So,

$\phi=3\times 10^3\times \pi\times (2.66)^2\ k$

$\phi=6.668\times 10^4\ Nm^2/C$

So, the electric flux through a circular area is $\phi=6.668\times 10^4\ Nm^2/C$ .Hence, this is the required solution.

6 0

2 years ago

In the case of the vacuum tube and movable stopper, what force moves the stopper?

sergejj [24]

I'm pretty sure it's the<span> impact of the air molecules on the outside of the stopper. They exert a net inward force, which is not resisted by anything on the other side.</span>

6 0

2 years ago

Read 2 more answers

If a proton and an electron are released when they are 2.50×10^-10m apart (typical atomic distances), find the initial accelerat

katrin [286]

To solve this exercise, we will first proceed to calculate the electric force given by the charge between the proton and the electron (it). From the Force we will use Newton's second law that will allow us to find the acceleration of objects. The Coulomb force between two charges is given as

$F = k \frac{q_1q_2}{r^2}$

Here,

k = Coulomb's constant

q = Charge of proton and electron

r = Distance

Replacing we have that,

$F = (9*10^9)(\frac{(1.602*10^{-19})^2}{2.5*10^{-10}})$

$F = 3.6956*10^{-9}N$

The force between the electron and proton is calculated. From Newton's third law the force exerted by the electron on proton is same as the force exerted by the proton on electron.

The acceleration of the electron is given as

$a_e = \frac{F}{m_e}$

$a_e = \frac{3.6956*10^{-9}}{9.11*10^{-31}}$

$a_e = 4.0566*10^{21}m/s^2$

The acceleration of the proton is given as,

$a_p = \frac{F}{m_p}$

$a_p = \frac{3.6956*10^{-9}}{1.672*10^{-27}}$

$a_p = 2.21*10^{18}m/s^2$

3 0

2 years ago

A ball rolls off a table and it traveling with a horizontal velocity of 2 m/s and 1 point

morpeh [17]

Answer:

The velocity when the ball hits the ground is obtained using v2. 2 = v1. 2 + 2 g Dy with v1=0 and Dy=h. Thus solving for v2 yields 17.1 m/s v2 = 2 g h =.

21 pages·330 KB

4 0

2 years ago

Read 2 more answers