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Dmitrij [34]
3 years ago
6

A rocket is moving with constant velocity of 2000ms and accelerates uniformly at 10ms. What is the velocity after 5 minutes?

Physics
1 answer:
AnnyKZ [126]3 years ago
8 0
The velocity is 300ml in 5 mins
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A ____ is a non solid state of matter in which the atoms and molecules are free to move past each other, as in a gas or liquid.
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The answer is GAS. In a gas, the particles are in a completely random motion in any direction. And it is not solid. Hope I helped. Good luck
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An object is allowed to fall freely near the surface of a planet. The object has an acceleration due to gravity of 24 m/s2. How
Alborosie

Answer:

12 m

Explanation:

The object is in uniformly accelerated motion, so the distance covered can be found using the following suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance

u is the initial velocity

t is the time

a is the acceleration

For this problem,

g=24 m/s^2

and

u = 0, since we are considering the first second of motion

So, substituting t = 1 s, we find

s=0+\frac{1}{2}(24)(1)^2=12 m

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An ice cube is placed on a hot stove. Which of these statements best describes how heat moves between the ice cube and the stove
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How does sound travel from its source to your ear?
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A hot air balloon is filled with 1.45 × 10 6 L of an ideal gas on a cool morning ( 11 ∘ C ) . The air is heated to 109 ∘ C . Wha
just olya [345]

Answer:

<em>The volume of air after the balloon is heated = 1.95 × 10⁶ L</em>

Explanation:

Charles Law: Charles' law states that the volume of a given mass of gas is directly proportional to the temperature in Kelvin, provided that the pressure remains constant.

It can be expressed mathematically as,

V₁/T₁ = V₂/T₂

Making V₂ The subject of the equation

V₂ = (V₁/T₁)T₂.................... Equation 1

Where V₁ = Initial Volume, T₁ = Initial Temperature, V₂ = Final Volume, T₂ = final Temperature

<em>Given: V₁ = 1.45 × 10⁶ L, T₁ = 11 °C = (11 + 273) K = 284 K, T₂ = 109 °C = (109 + 273) = 382 K.</em>

<em>Substituting these values into equation 1 above,</em>

<em>V₂ = (1.45×10⁶)382/284</em>

<em>V₂ = 1.95 × 10⁶ L</em>

<em>Therefore the volume of air after the balloon is heated = 1.95 × 10⁶ L</em>

6 0
3 years ago
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