<span>C. the slope of that objects velocity-time graph
Hope it helps!
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<span>When the question says the ball lands a distance of 235 meters from the release point, we can assume this means the horizontal distance is 235 meters.
Let's calculate the time for the ball to fall 235 meters to the ground.
y = (1/2)gt^2
t^2 = 2y / g
t = sqrt{ 2y / g }
t = sqrt{ (2) (235 m) / (9.81 m/s^2) }
t = 6.9217 s
We can use the time t to find the horizontal speed.
v = d / t
v = 235 m / 6.9217 s
v = 33.95 m/s
Since the horizontal speed is the speed of the plane, the speed of the plane is 33.95 m/s</span>
Answer:
A
Explanation:
The most important part about this is not only that objects pull on each other, but that two objects attract each other with a force that is proportional to the product of their masses and inversely proportional to the square of the distance between them. This is known as Newton's law of universal gravitation.
<span>Cool air from the shore will travel to the sea</span>
Answer:15.8 m/s
Explanation:
Given
Gravitational Force 
Air resistance 
mass of Parachutist 
Velocity after 
Now Parachutist opens the parachute
Net for on Parachutist
drag force
therefore deceleration 
velocity after 10 s is
