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3 years ago

Which statement is TRUE concerning the particle arrangement of a solid

Physics

2 answers:

Anni [7]3 years ago

8 0

It's packed together

Serhud [2]3 years ago

8 0

Answer:

Which statement is TRUE concerning the particle arrangement of a solid?

Particles of solid are closely packed together.

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A collapsible plastic bag (figure below) contains a glucose solution. If the average gauge pressure in the vein is 1.29 A collap

expeople1 [14]

Answer:

0.125 m

Explanation:

Pressure in fluids is given as the product of density, height and acceleration due to gravity and expressed as

P=hdg

Where h is the height, d is density, g is acceleration due to gravity and P is pressure.

Making h the subject of formula then

h=P/dg

Given specific gravity of a substance, its density is equal to specific gravity multiplied by density of water. Taking density of pure water as 1000 kg/m³ then the density of reference fluid will be 1.05*1000=1050 kg/m³

Substituting pressure with 1.29*10³ pa as given then taking g as 9.81 m/s² then

H=1.29*10³÷(9.81*1050)=0.1252366389981068880151448958788408329692m

Rounded off, the height is approximately 0.125 m

8 0

3 years ago

A light has a wavelength of 5.06x10-7m. what is the frequency of the light?

Artyom0805 [142]

So, the frequency of that light approximately $\sf{\bold{5.93 \times 10^{14} \: Hz}}$

<h3>Introduction</h3>

Hi ! Here I will help you to discuss the relationship between frequency and wavelength, with the velocity constant of electromagnetic waves in a vacuum. We all know that regardless of the type of electromagnetic wave, it will have the same velocity as the speed of light (light is part of electromagnetic wave too), which is 300,000 km/s or $\sf{3 \times 10^8}$ m/s. As a result of this constant property, <u>the shorter the wavelength, the greater the value of the electromagnetic wave frequency</u>. This relationship can also be expressed in this equation:

$\boxed{\sf{\bold{c = \lambda \times f}}}$

With the following condition :

c = the constant of the speed of light in a vacuum ≈ $\sf{3 \times 10^{8} \: m/s}$ m/s
$\sf{\lambda}$ = wavelength (m)
f = electromagnetic wave frequency (Hz)

<h3>Problem Solving</h3>

We know that :

c = the constant of the speed of light in a vacuum ≈ $\sf{3 \times 10^{8} \: m/s}$ m/s
$\sf{\lambda}$ = wavelength = $\sf{5.06 \times 10^{-7}}$ m.

What was asked :

f = electromagnetic wave frequency = ... Hz

Step by step :

$\sf{c = \lambda \times f}$

$\sf{3 \times 10^8 = 5.06 \times 10^{-7} \times f}$

$\sf{f = \frac{3 \times 10^8}{5.06 \times 10^{-7}}}$

$\sf{f \approx 0.593 \times 10^{8 - (-7)}}$

$\sf{f \approx 0.593 \times 10^{15}}$

$\boxed{\sf{f \approx 5.93 \times 10^{14} \: Hz}}$

<h3>Conclusion :</h3>

So, the frequency of that light approximately $\sf{\bold{5.93 \times 10^{14} \: Hz}}$

What affects photon energy brainly.com/question/26434060
What is the foton energy brainly.com/question/26518899

7 0

2 years ago

Stars are classified mainly according to their distance from Earth.

Zielflug [23.3K]

The answer is b) false. Stars are mainly classified by their spectra (the elements they absorb) and their temperature.

4 0

3 years ago

A steel sphere of mass 0.5kg travelling at 2m/s collides with an identical sphere at rest. What is the total momentum after coll

PSYCHO15rus [73]

Answer:

The total momentum after the collision is 1 kg-m/s.

Explanation:

We have,

Mass of a steel sphere is 0.5 kg

It is travelling with a speed of 2 m/s

It collides with an identical sphere at rest.

The law of conservation of momentum states that the initial momentum is equal to the final momentum for an isolated system. Here, initial momentum is :

$p_i=p_f=mv\\\\p_i=p_f=0.5\times 2\\\\p_f=1\ kg-m/s$

So, the total momentum after the collision is 1 kg-m/s.

3 0

3 years ago

What is the speed over the ground of an airplane flying at 100 km/h relative to the air caught in a 100-km/h right-angle crosswi

Rudiy27

Answer:

141.42 km/h

Explanation:

Since this is a 100km/h right angle crosswind, the speed vector with respect to the ground is the vector speed of the airplane with respect to air + the vector speed of the cross-wind with respect to the ground

<100,0> + <0,100> = <100,100>

This vector has a magnitude of

$v = \sqrt{v_1^2 + v_2^2} = \sqrt{100^2 + 100^2} = \sqrt{10000 + 10000} = \sqrt{20000} = 141.42$ km/h

4 0

3 years ago