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ASHA 777 [7]
4 years ago
10

Consider what will happen when a bar magnet is pushed toward the coil. when the coil "feels" the changing magnetic field caused

by the approach of the bar magnet, it will thereby become energized; a current will begin to flow through it, and the ammeter will register that current. this current is called an induced current because it has been induced by the person
Physics
1 answer:
notka56 [123]4 years ago
4 0
The question just basically explained what happens
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Un caballo parte del reposo y alcanza una velocidad de 15m/s en un tiempo de 8s. ¿ Cuál fue su aceleración y que distancia recor
Lemur [1.5K]

Answer: A 120 metros por segundo

Explanation: multiplicas la velocidad por el tiempo

7 0
3 years ago
How much net force is required to accelerate a 0.5 kg toy car, initially at rest to a velocity of 2.4 m/s in 6s?
Jet001 [13]
Force = 0.20N .F = m ×a .& a = v/t then the f = m×v/t

3 0
4 years ago
True<br> False<br><br> PLEASE HELP
harkovskaia [24]

Answer:

False

Explanation:

10 is not the same as -10 but if -10 is the absolute value they would be the  same

Give me brainllest

6 0
3 years ago
A wye-connected load has a voltage of 480v applied to it. What is the voltage drop across each phase
rodikova [14]

Answer:

Y_A=277.128 \angle 30v

Y_B=277.128 \angle (-150)v

Y_C=277.128 \angle (90)v

Explanation:

From the question we are told that

Voltage V_L_L =480v

Generally in a case of Y_connection V_p_ h is mathematical represented as

V_p_h=\frac{V_l_l}{\sqrt{3}} \angle (\phi-30)v

Generally voltage drop across phase A

Y_A=\frac{408}{\sqrt{3}} \angle -(0-30)

Y_A=277.128 \angle 30v

Generally voltage drop across phase B

Y_B=277.128 \angle (-30-120)

Y_B=277.128 \angle (-150)v

Generally voltage drop across phase C

Y_C=277.128 \angle (-30+120)

Y_C=277.128 \angle (90)v

3 0
3 years ago
You throw a ball upwards at 22.0 m/s how high will it go?
Alex

Answer:

Time to reach maximum height can be obtained from v=u+at

0=20+(−10)t

t=2s

s=ut+0.5at

2

=20(2)+0.5(−10)(2)

2

=20m

Thus, total distance for maximum height is 45 m

s=ut+0.5at

2

45=0+0.5(10)(t ′ )

2

t

′

=3s

Total time= 3+2= 5s

Explanation:

TAKE 22.0 IN PLACE OF 20 U WILL GET YR ANSWER

HOPE IT HELPS

3 0
3 years ago
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