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ASHA 777 [7]
4 years ago
10

Consider what will happen when a bar magnet is pushed toward the coil. when the coil "feels" the changing magnetic field caused

by the approach of the bar magnet, it will thereby become energized; a current will begin to flow through it, and the ammeter will register that current. this current is called an induced current because it has been induced by the person
Physics
1 answer:
notka56 [123]4 years ago
4 0
The question just basically explained what happens
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What do siesmic waves and sound waves have in common
MariettaO [177]

They're mechanical waves
7 0
3 years ago
8 m N &amp; 5 m 30° N of E<br><br> Draw and add the vectors.
Contact [7]

by vector addition.

< 5 m, 270 degrees> + < 8 cm, 90 degrees>

=< 500 cos 270, 500 sin 270 > + < 8 cos 90, 8 sin 90 >

=< 0, −500 > + < 0, −8 >

=< 0, −492 > cm

The so-called parallelogram law lays forth the guidelines for adding two or more vectors together. By aligning the two vectors A and B head to tail and drawing the vector from the free tail to the free head, the vector sum A+B is created. If A=(a 1,a 2,...,a n) and B=(b 1,b 2,...,b n), then vector addition can be done in Cartesian coordinates by adding the respective components of the vectors.

A+B=(a 1+b 1,a 2+b 2,...,a n+b n).

The Wolfram Language uses a plus symbol to denote vector addition, as in a1, a2,..., an+b1, b2,..., bn

to learn more about vector:

brainly.com/question/13322477

#SPJ4

3 0
2 years ago
A girl is out jogging at 2.00 m/s and accelerates at 1.50 m/s^2 until she reaches a velocity of 5.00 m/s. How far does she get?
Maksim231197 [3]

Answer:

7.00 m

Explanation:

Given:

v₀ = 2.00 m/s

v = 5.00 m/s

a = 1.50 m/s²

Find: Δx

v² = v₀² + 2aΔx

(5.00 m/s)² = (2.00 m/s)² + 2(1.50 m/s²)Δx

Δx = 7.00 m

5 0
3 years ago
A 910 kg car is approaching a loop-the-loop. The loop has a diameter of 50 m. Determine the minimum speed the car must have at t
scoundrel [369]

Answer:

The minimum speed the car must have at the top of the loop to not fall = 35 m/s

Explanation:

Anywhere else on the loop, the speed needed to keep the car in the loop is obtained from the force that keeps the body in circular motion around the loop which has to just match the force of gravity on the car. (Given that frictional force = 0)

mv²/r = mg

v² = gr = 9.8 × 25 = 245

v = 15.65 m/s

But at the top, the change in kinetic energy of the car must match the potential energy at the very top of the loop-the-loop

Change in kinetic energy = potential energy at the top

Change in kinetic energy = (mv₂² - mv₁²)/2

v₁ = velocity required to stay in the loop anywhere else = 15.65 m/s

v₂ = minimum velocity the car must have at the top of the loop to not fall

And potential energy at the top of the loop = mgh (where h = the diameter of the loop)

(mv₂² - mv₁²)/2 = mgh

(v₂² - v₁²) = 2gh

(v₂² - (15.65)²) = 2×9.8×50

v₂² - 245 = 980

v₂² = 1225

v₂ = 35 m/s

Hence, the minimum speed the car must have at the top of the loop to not fall = 35 m/s

4 0
3 years ago
The period of time required for the moon to complete a cycle of phases is called the ________ month.
eduard
Synodic month, also known as a lunar month.
3 0
3 years ago
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