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vovangra [49]
4 years ago
15

Identify the variable that is manipulated in an experiment.

Chemistry
2 answers:
BARSIC [14]4 years ago
8 0

the answer is (#1) independent variable.

Blababa [14]4 years ago
7 0
Independent Variable
 i hope I've helped!
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The surface forces that change the surface of the earth are:
pshichka [43]
Number one victory royal yaaa
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3 years ago
Can someone help im not good at science
Digiron [165]

Answer:

B

Explanation:

The products are what come out of the mix.

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Which of the following solutes has the greatest effect on the colligative properties for a given mass of pure water? Explain.
Strike441 [17]

Answer:

Option a.

0.01 mol of CaCl₂ will have the greatest effect on the colligative properties, because it has the biggest i

Explanation:

To determine which of the solute is going to have a greatest effect on colligative properties we have to consider the Van't Hoff factor (i)

These are the colligative properties:

ΔP = P° . Xm . i  →  Lowering vapor pressure

ΔT = Kb . m . i  → Boiling point elevation

ΔT = Kf . m . i  →  Freezing point depression

π = M . R . T  →  Osmotic pressure

Van't Hoff factor are the numbers of ions dissolved in the solution. For nonelectrolytes, the i values 1.

CaCl₂ and KNO₃ are two ionic solutes. They dissociate as this:

CaCl₂  → Ca²⁺ + 2Cl⁻

We have 1 mol of Ca²⁺ and 2 chlorides, so 3 moles of ions → i = 3

KNO₃ → K⁺ + NO₃⁻

We have 1 mol of K⁺ and 1 mol of nitrate, so 2 moles of ions → i = 2

Option a, is the best.

8 0
3 years ago
Write some example of misicible and immisicible liquid​
Eduardwww [97]

Explanation:

miscible liquids: water and alcohol

immiscible liquids: water and oil

4 0
3 years ago
What is the enthalpy change (in kJ) of a chemical reaction that raises the temperature of 250.0 ml of solution having a density
stellarik [79]

Answer:

328.4KJ

Explanation:

Before we move on to calculate enthalpy change, we calculate the amount of heat Q

Q= mcΔT

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ΔT = 7.80 + 273.15K = 280.95K

Q= 312.5 * 3.74 * 280.95 = 328,360.312 J= 328.4KJ(1000J = 1KJ, so divide by 1000)

The enthalpy change in the reaction is same as amount of heat transferred = 328.4KJ

3 0
4 years ago
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