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sergey [27]
4 years ago
12

Which is true about surface waves?

Physics
2 answers:
Firlakuza [10]4 years ago
5 0
I got A.) The disturbance is only parallel to the motion of the wave
posledela4 years ago
3 0
I think the answer is A 
.
im not the best with physics but i think its right 
You might be interested in
Calculate the object's velocity as shown on the position-time graph,
Cloud [144]

Answer:

10 m/s

Explanation:

The following data were obtained from the question:

Initial Displacement (d1) = 10 m

Final Displacement (d2) = 60 m

Initial time (t1) = 0 s

Final time (t2) = 5 s

Velocity (v) =.?

Next, we shall determine the change in displacement of the object and likewise the change in time.

This can be obtained as follow:

Initial Displacement (d1) = 10 m

Final Displacement (d2) = 60 m

Change in displacement (Δd) = d2 – d1

Change in displacement (Δd) = 60 – 10

Change in displacement (Δd) = 50 m

Initial time (t1) = 0 s

Final time (t2) = 5 s

Change in time (Δt) = t2 – t1

Change in time (Δt) = 5 – 0

Change in time (Δt) = 5 s

Finally, we shall shall calculate the velocity of the object as illustrated below:

Change in displacement (Δd) = 50 m

Change in time (Δt) = 5 s

Velocity (v) =.?

v = Δd/Δt

v = 50/5

v = 10 m/s

Therefore, the velocity of the object is 10 m/s.

4 0
3 years ago
What is the Kinetic Energy of a pie with a mass of 5 kg travelling at a velocity of 9m/s towards your face ?
Stolb23 [73]

Answer:

K = 202.5 J

Explanation:

Given that,

Mass of pie is 5 kg

Velocity of pie is 9 m/s

We need to find the kinetic energy of a pie. The kinetic energy of an object is due to its motion. It can be given by the formula as follows :

K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 5\times (9)^2\\\\K=202.5\ J

So, the kinetic energy of the pie is 202.5 J.

4 0
3 years ago
A 300 g block connected to a light spring with a force constant of k = 3 N/m is free to oscillate on a horizontal, frictionless
Usimov [2.4K]

Answer:

Time period, T = 1.98 seconds

Explanation:

It is given that,

Mass of the block, m = 300 g = 0.3 kg

Force constant of the spring, k = 3 N/m

Displacement in the block, x = 3 cm

Let T is the period of the motion of the block. The time period of the block is given by :

T=2\pi \sqrt{\dfrac{m}{k}}

T=2\pi \sqrt{\dfrac{0.3\ kg}{3\ N/m}}    

T = 1.98 seconds

So, the period of the motion of the block is 1.98 seconds. Hence, this is the required solution.

7 0
3 years ago
When bouncing a ball, the bouncing motion results in the ball ____________.
yan [13]

Answer:

B) changing position

Explanation:

When a ball bounces to the ground it hits the ground with some energy. The amount of energy with which it hits the ground is kinetic energy. When it comes in the contact with the ground kinetic energy gets converted into potential energy. This potential energy again gets converted into kinetic energy and balls moves again from the ground and bounces multiple times. So, due to multiple bounce the position of the ball changes.

Thus, When bouncing a ball, the bouncing motion results in the ball changing position.

6 0
4 years ago
Read 2 more answers
The Magnetic Dipole Moment of a Coil Problem A rectangular coil of dimensions 5.40 cm ✕ 8.50 cm consists of 25 turns of wire and
butalik [34]

Answer:

a

 \mu =  0.0023 \ A\cdot m^2

b

\tau  =    0.00080  \  N \cdot  m

Explanation:

From the question we are told that

  The dimensions of the  rectangular coil is 5.40 cm ✕ 8.50 cm  = 0.054 m X 0.085 m

   The  number of turns is  N  = 25 \ turns

   The current it  is carrying is  I = 20 \ mA  = 0.02 \  A

    The magnetic field is B = 0.350 \   T

Generally the magnitude of the magnetic dipole moment is mathematically represented as

       \mu = N  *  I *  A

Here  A  is the area which is mathematically represented as

     A =  0.054  * 0.085

=>  A =  0.00459 \  m^2

So  

     \mu = 25  * 0.02 *  0.00459

=>  \mu =  0.0023 \ A\cdot m^2

Generally the  magnitude of the torque acting on the loop is mathematically represented as

    \tau  =  \mu * B

=>\tau  =    0.0023  * 0.350

=>\tau  =    0.00080  \  N \cdot  m

8 0
3 years ago
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