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Naily [24]
3 years ago
15

A child pushes a toy car down a hill. The child has a mass of 20 kg. The car has a mass of 1.6 kg and a speed of 7.4 m/s2. When

the car has a gravitational potential energy of 30 J, what is the mechanical energy of the car?
Physics
1 answer:
Andrew [12]3 years ago
5 0

Answer:

The answer is 73.8 J

Explanation:

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At a waterpark, sleds with riders are sent along a slippery, horizontal surface by the release of a large, compressed spring. Th
jekas [21]

Answer:

2.2 m/s

Explanation:

<u>solution:</u>

To calculate change in stored energy at desired extension

ΔU = 1/2*k*(δx)^2

     = 1/2*3700*(0.37^2-0.180^2)

     = 201 N.m

use work energy theorem

ΔU = ΔK = 1/2*m*v^2 = 201

              = 2.2 m/s

<u>note:</u>

calculation maybe wrong but method is correct.

8 0
4 years ago
Read 2 more answers
A carton is given a push across a horizontal, frictionless surface. The carton has a mass m, the push gives it an initial speed
sammy [17]

Answer and Explanation:

Data provided in the question

Carbon mass = m

Initial speed = v_i

Coefficient = μk

Based on the above information, the expressions are as follows

a. By using the energy considerations the expression for the carton moving distance is

As we know that

Fd = \frac{1}{2} m (v_i^2- v_f^2)

where,

v_f = 0

F = u_kmg

(\mu_kg) d = \frac{1}{2} m v_i^2

d = \frac{\frac{1}{2}v_i^2}{\mu_kg}

d = \frac{v_i^2}{2 \mu_kg}

b. The initial speed of the carton if the factor of 3 risen, so the expression is

v_i^1 = 3v_i

d^i = \frac{(3v_i^2)}{2\mu_kg}

= \frac{9v_i^2}{2\mu_kg}

d^i = 9(d)

8 0
4 years ago
Use the table of electric force between objects in two different interactions to answer the question. Interaction Charge on Obje
forsale [732]

Answer:?that’s a lot

Explanation:

6 0
3 years ago
Monochromatic light falls on two very narrow slits 0.048 mm apart. successive fringes on a screen 5.00 m away are 6.5 cm apart n
atroni [7]
In a double-slit interference experiment, the distance y of the maximum of order m from the center of the observed interference pattern on the screen is
y= \frac{m \lambda D}{d}
where D=5.00 m is the distance of the screen from the slits, and 
d=0.048 mm=0.048 \cdot 10^{-3}m is the distance between the two slits.
The fringes on the screen are 6.5 cm=0.065 m apart from each other, this means that the first maximum (m=1) is located at y=0.065 m from the center of the pattern.
Therefore, from the previous formula we can find the wavelength of the light:
\lambda =  \frac{yd}{mD}= \frac{(0.065 m)(0.048 \cdot 10^{-3}m)}{(1)(5.00 m)}=  6.24 \cdot 10^{-7}m

And from the relationship between frequency and wavelength, c=\lambda f, we can find the frequency of the light:
f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{6.24 \cdot 10^{-7}m}=4.81 \cdot 10^{14}Hz
4 0
3 years ago
Anthony walks to the pizza place for lunch. He walk 1km east, then 1km south and then 1km east again. What distance did he cover
Komok [63]

Answer:

Pizza pizzza pizza

Explanation:

little ceasrs

8 0
3 years ago
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