Acceleration in m/s^2 = 2/10 = 0.2 m/s^2
Answer:
The final velocity of the thrower is 
and the final velocity of the catcher is 
.
Explanation:
Given:
The mass of the thrower, 
.
The mass of the catcher, 
.
The mass of the ball, 
.
Initial velocity of the thrower, 
Final velocity of the ball, 
Initial velocity of the catcher, 
Consider that the final velocity of the thrower is 
. From the conservation of momentum,
Consider that the final velocity of the catcher is 
. From the conservation of momentum,
Thus, the final velocity of thrower is 
and that for the catcher is 
.
Answer:
Explanation:
Since the hoop is rolling on the floor so its total kinetic energy is given as
now for pure rolling condition we will have
also we have
now we will have
now by work energy theorem we can say
now solve for final speed
For the same reason that you can skate around a curve at constant speed but not with constant velocity.
The DIRECTION you're going is part of your velocity, but it's not part of your speed.
If the DIRECTION changes, that's a change of velocity.
The object doesn't have to change speed to have a different velocity. A change of direction is enough to do it.
And any change of velocity is called acceleration.
Answer: 0.006in/s
Explanation:
Let the rate at which air is being blown into a spherical balloon be dV/dt which is 1.68in³/s
Also let the rate at which the radius of the balloon is increasing be dr/dt
Given r = 4.7in and Π = 3.14
Applying the chain rule method
dV/dt = dV/dr × dr/dt
If the volume of the sphere is 4/3Πr³
V = 4/3Πr³
dV/dr = 4Πr²
If r = 4.7in
dV/dr = 4Π(4.7)²
dV/dr = 277.45in²
Therefore;
1.68 = 277.45 × dr/dt
dr/dt = 1.68/277.45
dr/dt = 0.006in/s
