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Sedbober [7]
3 years ago
15

When would a scientist accept the alternative

Physics
1 answer:
vredina [299]3 years ago
3 0

Answer:

B.) if statistical results are significant

Explanation:

If a scientist accepts the null hypothesis, then there is enough evidence to reject the null hypothesis.

This means that the p-value is less than the significance level.

When the scientist accepts the alternative hypothesis, it means the statistical results are significant.

The correct answer is B.

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Which object is I’m equilibrium?
IrinaK [193]

Equilibrium is a state of no motion. If donuts are on the table, they are in equilibrium. Literally anything that is NOT moving relative to the earth is in equilibrium. The chair is in equilibrium, the table is in equilibrium, the cookies are in equilibrium, and so on.

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A student wants you to demonstrate that an electric current will produce a magnetic field. Which set of objects could be used to
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A. a battery a coil of wire and a compass
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3 years ago
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A force F = (2.75 N)i + (7.50 N)j + (6.75 N)k acts on a 2.00 kg mobile object that moves from an initial position of d = (2.75 m
Natasha2012 [34]

Answer:

The work done on the object by the force in the 5.60 s interval is 40.93 J.

Explanation:

Given that,

Force F=(2.75\ N)i+(7.50\ N)j+(6.75\ N)k

Mass of object = 2.00 kg

Initial position d=(2.75)i-(2.00)j+(5.00)k

Final position d=-(5.00)i+(4.50)j+(7.00)k

Time = 4.00 sec

We need to calculate the work done on the object by the force in the 5.60 s interval.

Using formula of work done

W=F\cdot d

W=F\cdot(d_{f}-d_{i})

Put the value into the formula

W=(2.75)i+(7.50)j+(6.75)k\cdot (-(5.00)i+(4.50)j+(7.00)k-(2.75)i+(2.00)j-(5.00)k)

W=(2.75)i+(7.50)j+(6.75)k\cdot((-7.75)i+6.50j+2.00k)

W=2.75\times-7.75+7.50\times6.50+6.75\times2.00

W=40.93\ J

Hence, The work done on the object by the force in the 5.60 s interval is 40.93 J.

4 0
3 years ago
Contrast generators and electric motors.
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Generators take mechanical and output energy. electric motors take the input of electricity. 
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3 years ago
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A crane carries a 1600 kg car at 1.5 m/s^2 with a chain that has a negligible mass. If the coefficient of kinetic friction betwe
padilas [110]

Answer:

option (d) 7.1 kN

Explanation:

Given:

Mass of the car, m = 1600 kg

Acceleration of the car, a = 1.5 m/s²

Coefficient of kinetic friction = 0.3

let the tension be 'T'

Now,

ma = T - f .................(1)

where f is the frictional force

also,

f = 0.3 × mg

where g is the acceleration due to the gravity

thus,

f = 0.3 × 1600 × 9.81 =

therefore,

equation 1 becomes

1600 × 1.5 = T - 4708.8

or

T = 2400 + 4708.8

or

T = 7108.8 N

or

T = 7.108 kN

Hence,

The correct answer is option (d) 7.1 kN

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3 years ago
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