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Feliz [49]
3 years ago
13

How much energy, in Joules, is needed to raise the temperature from 25.87°C to 33.16°C in a 2.66 kg block of each of the followi

ng materials? Silver has a specific heat of 0.235 J/g·K, iron has a specific heat of 0.449 J/g·K, and titanium has a specific heat of 0.522 J/g·K. (a) silver
Physics
1 answer:
RUDIKE [14]3 years ago
6 0

Answer:

(a) Silver, H = 455.67 J

(b) Iron, H = 870.67 J

(c) titanium, H = 1012.23 J

Explanation:

mass of block, m = 2.66 kg = 266 g

T1 = 25.87° C

T2 = 33.16° C

ΔT = T2 - T1 = 33.16 - 25.87 = 7.29° C

(a) Specific heat of silver, c = 0.235 J/g K

The heat required is given by

H = m x c x ΔT

H = 266 x 0.235 x 7.29 = 455.67 J

(b) Specific heat of iron, c = 0.449 J/g K

The heat required is given by

H = m x c x ΔT

H = 266 x 0.449 x 7.29 = 870.67 J

(c) Specific heat of titanium, c = 0.522 J/g K

The heat required is given by

H = m x c x ΔT

H = 266 x 0.522 x 7.29 = 1012.23 J

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The absolute temperature of a sample of monatomic ideal gas is doubled at constant volume. What effect
Advocard [28]
<h3><u>Answer;</u></h3>

Doubles and Remains the same

<h3><u>Explanation;</u></h3>
  • The effect of doubling the absolute temperature of a sample of a monoatomic ideal gas is that,the pressure doubles and density of the sample of gas remains the same.
  • <em><u>According to ideal gas equation; PV = nRT; Where P is pressure and V is the Volume, n is the number of moles, R is the ideal gas constant and T is the absolute temperature.</u></em>
  • <em><u>Therefore, when the temperature of the mono atomic ideal gas is doubled, the pressure of the gas will also doubles.</u></em>
  • However, in a closed chamber mass of the ideal gas is invariant, since density depends only on the mass and volume therefore the density of the ideal is gas will remain the same.
5 0
3 years ago
A sodium ion, Na+ , has a positive charge because it
goldenfox [79]

D. lost an electron

because they have free electron in the outermost shell which they will like to denote, in order to attain stable configuration

3 0
3 years ago
An ion of an element has 30 protons 32 neutrons and 29 electrons what is that charge and how did you make that determination
ale4655 [162]

The ion has a charge of 1 +.

A neutral ion would have the same number of protons and neutrons. The neutrons have no charge (they're neutral) so they don't matter when it comes to the charge of an ion. This ion has 30 protons (+) and 29 electrons (-). There is 1 more proton than there are electrons so the ion has a charge of 1 +.

4 0
3 years ago
Read 2 more answers
A plane takes off from an airport and flies to town A, located d1 = 335 km from the airport in the direction 20.0° north of east
gtnhenbr [62]

Answer:

R = 545.38 m ; θ = 28.43°

Explanation:

given,

for town A : d₁ = 335 km at an direction of 20° north of east

for town B : d₂ = 245 km at  30.0° west of north from town A

x = 335 cos 20° + 245 sin 30°

x = 437.29 m

y = 335 sin 20° + 245 cos 30°

y = 326.75 m

resultant = \sqrt{x^2+y^2}

R =\sqrt{437.29^2+326.75^2}

R = 545.38 m

tan \theta = \dfrac{326.75}{437.29}

θ = 28.43°

4 0
4 years ago
What is the wavelength in nanometers of light when the energy is 1. 91 × 10^6 j for a mole of photons?.
JulijaS [17]

The wavelength in nanometers of light when the energy is 1. 91 × 10^6 j for a mole of photons is <u>62. 8 nm.</u>

Wavelength is the distance among the same points (adjacent crests) within the adjoining cycles of a waveform signal propagated in space or along a cord. In wi-fi structures, this period is typically specified in meters (m), centimeters (cm), or millimeters (mm).

The wavelength is the distance between wave crests, and it is going to be the same for troughs. The frequency is the variety of vibrations that skip over a given spot in one 2nd, and it's far measured in cycles consistent with the second (Hz) (Hertz).

Frequency is the ratio of pace and wavelength in relation to speed. In comparison, wavelength refers to the ratio of pace and frequency. Audible sound waves are characterized by way of a frequency range of 20 to 20 kHz. In contrast, the variety of wavelengths of visible light is from four hundred to seven hundred nm.

<u>calculation:-</u>

*E=hc/λ

1.91 × 10^6 J = (6.62610⁻³⁴) (3.00*10⁸) / λ

λ= (6.62610⁻³⁴) (3.00*10⁸) / 1.91 × 10⁶ J

λ= 1.0410⁻³¹× 10⁻⁹ × 6.022*10²³

 =<u> 62. 8 nm </u>

Learn more about wavelength here:-brainly.com/question/10728818

#SPJ4

6 0
1 year ago
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