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WITCHER [35]
3 years ago
8

Help please :) 15 points.

Physics
1 answer:
ladessa [460]3 years ago
5 0

Answer:

south

Explanation:

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What is the energy in joules of a photon with a frequency of 3.16e 12 s-1?
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We have: Energy(E) = Planck's constant(h) × Frequency(∨)
Here, Planck's constant(h) = 6.626 × 10⁻³⁴ J/s
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