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Vsevolod [243]
3 years ago
11

Which statements correctly describe water boiling in a pot?

Chemistry
2 answers:
Sergeeva-Olga [200]3 years ago
7 0
Gaining potential energy
Soloha48 [4]3 years ago
6 0
C. The water is gaining internal potential energy.
D. The water’s temperature is increasing.
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How does the scientific process generally begin
e-lub [12.9K]
It begins by trying to solve a problem and or making a hypothesis.
7 0
3 years ago
How many molecules is 2.03 moles of Al(SO4)3?​
Elena L [17]
2.03 molecules times 6.022E23 = 1.22E24
4 0
3 years ago
In Part A, you found the number of moles of product (1.80 mol P2O5 ) formed from the given amount of phosphorus and excess oxyge
n200080 [17]

Answer:

1.40 moles.

Explanation:

The balanced chemical equation for the reaction of Phosphorus and Oxygen is as follows -

4P + 5O_2 = 2P_2O_5

In Part A, the oxygen was taken in excess. So Phosphorus will be the limiting reagent.

Since, 2 moles of P_2O_5 is formed by 4 moles of P

So, for 1.8 moles of  P_2O_5 amount of required moles of P = \frac{4}{2} \times 1.80 = 3.60

In Part B, the phosphorus was taken in excess so oxygen will be the limiting reagent.

Since, 2 moles of P_2O_5 is formed by 5 moles of oxygen

So, for 1.40 moles of P_2O_5 moles of O_2 required = \frac{5}{2} \times 1.40 = 3.50

Thus as of now we have 3.60 moles of P_2O_5 and 3.50 moles of O_2.

As in the reaction of formation of P_2O_5, oxygen is the limiting reagent.

So the moles of P_2O_5 formed by the 3.50 moles of oxygen will be

P_2O_5 = \frac{2}{5} \times 3.50 = 1.40 moles.

5 0
3 years ago
Water is flowing in a pipe with a mass flow rate of 100.0 lb/h (M water H,O=18.016). What is the (i) Molar flow rate of H20 (gmo
Arada [10]

Answer:

i) 0,7 molH20/s

ii)11,2 g O/s

iii)1,4 g H/s

Explanation:

i) To find the molar flow rate of water, we just convert the mass of water to moles of water using its molecular weight(g/mol) and changing to the proper units (lb to grames and hours to seconds):

100 \frac{lb}{h}*\frac{453,5g}{1 lb}*\frac{1molH20}{18,016g}*\frac{1h}{3600s}=0,7\frac{molH20}{s}

ii) Now we just consider the oxygen in the water stream (for 1 mole of water there is 1 mole of oxygen):

100\frac{lb}{h} *\frac{453,5g}{1lb}*\frac{1 molH20}{18,016g}*\frac{1molO}{1molH20}*\frac{16gr}{1molO}*\frac{1h}{3600s}=11,2\frac{gO}{s}

iii)Just considering the hydrogen in the stream (for 1 mole of water there is 2 moles of hydrogen):

100\frac{lb}{h} *\frac{453,5g}{1lb}*\frac{1 molH20}{18,016g}*\frac{2molH}{1molH20}*\frac{1gr}{1molH}*\frac{1h}{3600s}=1,4\frac{gH}{s}

3 0
3 years ago
Which subatomic particle is the lightest?
NikAS [45]
Your answer is:

C. Electron


5 0
4 years ago
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